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mash [69]
3 years ago
6

Outside of the mirror in your bathroom (or bedroom), how else are you using mirrors in your daily life?

Physics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:

Explanation:

Mirrors are widely used in our day to day life for example

1.E.N.T. specialist used a concave mirror to see the clear and better image of the infected part.

2. A convex mirror is used in vehicles as a rear-view mirror. It covers a large area, so it is commonly used in vehicles.

3. Convex mirrors are generally utilized for making magnifying glasses

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object is placed 15cm in front of a plane mirror. If the mirror is moved further 5cm away from the object and the image is​
solong [7]

Answer:

The image will most likely be 20cm in front the mirror since the mirror was placed further 5cm.

4 0
2 years ago
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Your classmate says that if all the molecules in a particular liquid had the same speed, and some were able to evaporate, the re
babymother [125]
The molecules which evaporate presumably take heat away from the liquid. So, I'd disagree with the classmate. Whether the amount of cooling would differ from the usual case wherein the molecules have different speeds is another question. 
I guess the argument goes something along the lines of that the faster moving and therefore most kinetically energetic molecues evaporate and take away most heat. But if there's no faster moving molecules, 'cos they all have the same speed well, then presumably they'd all take away the same amount of heat. So, maybe the cooling would be less. No cooling though ??? Hmmmm dunno .... i think not ....
3 0
3 years ago
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Based on experimental observations, the acceleration of a particle is defined by the relation a = -(0.1 + sin x/b), where a and
Fiesta28 [93]

Answer:

Velocity,v = 0.323 m/s

Explanation:

The acceleration of a particle is given by :

a=-(0.1+sin\dfrac{x}{b})

b = 0.8 m when x = 0

Since, a=v\dfrac{dv}{dx}  

v\dfrac{dv}{dx}=-(0.1+sin\dfrac{x}{b})  

\int{v.dv}=\int{-(0.1+sin\dfrac{x}{b})}.dx

\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]+c

At x = 0, v = 1 m/s

\dfrac{1}{2}=0.8+c

c=-0.3

\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]-0.3

At x = -1 m

\dfrac{v^2}{2}=-0.1(-1)+0.8cos\dfrac{(-1)}{0.8}-0.3

{v^2}=0.1045

v = 0.323 m/s

So, the velocity of the particle is 0.323 m/s. Hence, this is the required solution.

8 0
3 years ago
How fast must a 1000 kg car be moving to have a kinetic energy of 2.0*10^3
lawyer [7]
Kinetic Energy is defined by Ke=1/2mv^2. Plug in and solve for v.

2,000 = 1/2(1000)(v)^2
4=(v)^2
v=2 m/s

The car must move at 2 m/s to have a Ke of 2,000 Joules.
6 0
2 years ago
A sack of groceries with a mas of 22 kg is lifted off the floor with a velocity of 6 m/s. What is the kinetic energy of the sack
AnnyKZ [126]

the answer is 396 joules :D

5 0
3 years ago
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