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mash [69]
3 years ago
6

Outside of the mirror in your bathroom (or bedroom), how else are you using mirrors in your daily life?

Physics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:

Explanation:

Mirrors are widely used in our day to day life for example

1.E.N.T. specialist used a concave mirror to see the clear and better image of the infected part.

2. A convex mirror is used in vehicles as a rear-view mirror. It covers a large area, so it is commonly used in vehicles.

3. Convex mirrors are generally utilized for making magnifying glasses

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Which of the following is a common downside of net pens, one of the most common forms of aquaculture?
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Answer is overcrowding aka answer choice A. I got the question and got it right. Please mark brainliest. Have a good day! :)

Explanation:

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3 years ago
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Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an angle of 63.0
valentina_108 [34]

Answer:

willie tower

Explanation:

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2 years ago
Identify the law, write the equation and calculate the answer to the problem below.
lyudmila [28]

Find refractive index first

\\ \rm\Rrightarrow \mu=\dfrac{c}{v}

\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}

\\ \rm\Rrightarrow \mu =0.75

Now

\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu

\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75

\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr

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2 years ago
What is the difference between the inner and outer planets?
max2010maxim [7]
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3 years ago
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A parallel-plate capacitor is connected to a battery and becomes fully charged. The capacitor is then disconnected, and the sepa
AnnZ [28]

Answer:

Increases

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The expression for the capacitance is as follows as;

C=\frac{\epsilon _{0}A}{d}

Here, C is the capacitance, \epsilon _{0} is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.

It can be concluded from the above expression, the capacitance is inversely proportional to the distance. According to the given problem, the capacitor is disconnected from the battery and the distance between the plates is increased. Then, the capacitance of the given capacitor will decrease in this case.

The expression for the energy stored in the parallel plate capacitor is as follows;

E=\frac{Q^{2}}{2C}

Here, E is the energy stored in the capacitor, C is the capacitance and Q is the charge.

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Therefore, the option (c) is correct.

8 0
3 years ago
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