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kozerog [31]
3 years ago
8

25 percent of what is 38?

Mathematics
1 answer:
AnnyKZ [126]3 years ago
8 0

Answer: 152

Step-by-step explanation:

Let the number = x.

Therefore, x*25% = 38

25% as a decimal is 0.25.

So, 0.25x = 38

We can divide both sides by 0.25:

x = 152

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Step-by-step explanation:

I would assume the answer would be a. 18 assuming your trying to find the entire value of a triangle but have a missing value

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A football field is marked every 5 yards. Garret ran from the 1st mark to the 11th mark. Which shows the correct way to find the
svlad2 [7]

Answer:

150 feet

Step-by-step explanation:

There are 10 marks between the 1st and 11th mark.

Since each mark represents 5 yards, 10 * 5 = 50 yards

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Mai is visiting Paris to see the Eiffel Tower. She is 80 feet away
Jlenok [28]

Answer: height of the tower is 1064 feet

Step-by-step explanation:

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Assuming her line of sight of the top of the tower is a straight line, then a right angle triangle is formed. The height, h of the tower represents the opposite side of the triangle. Her distance from the foot of the tower represents the adjacent side of the triangle.

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Therefore,

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7 0
3 years ago
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4. Mary has 21 coins whose total value is Kshs. 72. There are twice as many five
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3 years ago
Saturn is 8.867 × 10^8 miles away from the Sun. Uranus is 1.787 × 10^9 miles away from the Sun. Approximately how many times far
Over [174]

Answer:

<em>2 times </em>

<em></em>

Step-by-step explanation:

Please refer to the image attached of our <em>solar system </em>in which Saturn and Uranus are clearly visible.

Distance of Saturn from Sun, D_{1} = 8.867 \times 10^{8}\ miles

Distance of Uranus from Sun, D_{2} = 1.787 \times 10^{9}\ miles

We have to find, how many times the Uranus is far from Sun than Saturn is far from Sun.

Let us begin by multiplying the distance of Saturn from Sun by 2: D_{1} \times 2 = 8.867 \times 10^{8}\ miles \times 2\\\Rightarrow 17.734 \times 10^{8}\ miles\\\Rightarrow 1.7734 \times 10^{1} \times  10^{8}\ miles\\\Rightarrow 1.7734 \times 10^{8+1}\  miles\\\Rightarrow 1.7734 \times 10^{9} $\approx$ D_{2}

From above, we can say that D_{2} is approximately <em>twice </em>of D_{1}.

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