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Lilit [14]
2 years ago
11

Solve for x need help asap pls will give brainliest

Mathematics
1 answer:
Basile [38]2 years ago
7 0

Step-by-step explanation:

tangent forms a right angle with radius of circle

so (6.8+10.2)^2 = 10.2^2 + x^2

x= 13.6

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Explain how 3^7 + 2 must be an odd number
Firdavs [7]
It must be an odd number because 3^7 is also shown as:
3x3x3x3x3x3x3

Which equals:2,187

2,187 is an odd number because the last number is a 7 which is odd.
5 0
1 year ago
Can anybody help me with this problem 324 divided by 2,456?
UNO [17]

Answer:

0.13192182

Step-by-step explanation:

324/2456

To solve, divide.

324/2456

This equals:

0.13192182

Hope this helps!

3 0
3 years ago
Zoey solved the calculation 5 + 3.89 using a decimal number line. The decimal number line shows how Zoey calculated the answer.
IceJOKER [234]
Start at the point 0
Then move 5 points right because 5 is positive
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Sooo 5 + 3.89 = 8.89

Hope this helps :D
4 0
3 years ago
Write the equation of the quadratic function with roots 0 and 2 and a vertex at (1,5).
lisov135 [29]

Answer:

Step-by-step explanation:

y=a(x-0)(x-2)

=a(x^2-2x)

=a(x^2-2x+1-1)

or y=a(x-1)^2-a

(1,5) lies on it.

5=a(1-1)^2-a

5=0-a

or a=-5

so y=-5(x-1)^2+5

8 0
2 years ago
The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.
zhuklara [117]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(t)=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{19}t+110~\hspace{10em}19~\frac{ft}{sec}

3 0
3 years ago
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