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Fudgin [204]
2 years ago
11

A. Calculate the molarity of solution of "sodium sulfate" that contains 5.2 grams sodiums sulfate diluted to 500mL.

Chemistry
1 answer:
Fynjy0 [20]2 years ago
5 0

A. The molarity of solution containing 5.2 g of sodium sulphate is 0.0732 M

B. The number of mole of sodium in the solution is 0.0732 mole

<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
  • Mass of Na₂SO₄ = 5.2 g
  • Molar mass of Na₂SO₄ = (23×2) + 32 + (16×4) = 142 g/mol
  • Mole of Na₂SO₄ =?

Mole = mass / molar mass

Mole of Na₂SO₄ = 5.2 / 142

Mole of Na₂SO₄ = 0.0366 mole

<h3>A. How to determine the molarity </h3>
  • Mole of Na₂SO₄ = 0.0366 mole
  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Molarity =?

Molarity = mole / Volume

Molarity = 0.0366 / 0.5

Molarity = 0.0732 M

<h3>B. How to determine the mole of sodium (Na) </h3>

1 mole of Na₂SO₄ contains 2 moles of Na.

Therefore,

0.0366 mole of Na₂SO₄ will contain = 0.0366 × 2 = 0.0732 mole of Na

Thus, 0.0732 mole of Na is present in the solution.

Learn more about molarity:

brainly.com/question/15370276

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Answer:

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Explanation:

The electric field of a point charge can be calculated using the next equation:

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\epsilon_0=Absolute\hspace{3}permittivity\hspace{3}of\hspace{3}free\hspace{3}space\approx 8.85\times 10^{-12} \\Q=Charge\hspace{3}magnitude\\r=Distance

The distance can be calculated as:

r=\sqrt{0.5^2+0^2+0^2} =0.5

Using the data provided by the problem:

E=\frac{1}{4\pi (8.85\times 10^{-12}) } \frac{1\times 10^{-9} }{0.5^2} =35.96721878\approx35.97V/m

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4 years ago
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The definition of <em>equilibrium</em> is when the forward rate and the reverse rate are <em>equal</em>.

Because in the initial state there's only NO₂, there's no possibility for the reverse reaction (from N₂O₄ to NO₂). Thus the forward rate will be larger than the reverse rate.

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What is the difference between qualitative data and quantitative data?
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How many moles of compound are there in the following?
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b) The molar mass for Ca(OH)2 = 74.0 g/mole, calculated like (NH4)2SO4 above.

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This is so because a chemical that is unknown amounts to the fact that what such chemical contains is unknown, hence, the chemical might have the ability to cause harm or injuries to the sense organ. For example, a conc. acid that is tasted will burn the tongue etc.

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