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mojhsa [17]
4 years ago
12

Reacts most vigorously with water

Chemistry
1 answer:
hram777 [196]4 years ago
8 0
<span>The answer is - a. Alkali Metal. 
</span>They react violently with water to form alkaline solutions. This is because they all have 1 electron in their outer shell and losing 1 electron allows them to have full outer shells, and achieve stability.

<span>

</span>
You might be interested in
The pH of a 0.78M solution of 4-pyridinecarboxylic acid HC6H4NO2is measured to be 2.53.Calculate the acid dissociation constant
nika2105 [10]

Answer : The value of acid dissociation constant is, 1.1\times 10^{-5}

Solution :  Given,

Concentration pyridinecarboxylic acid = 0.78 M

pH = 2.53

First we have to calculate the hydrogen ion concentration.

pH=-\log [H^+]

2.53=-\log [H^+]

[H^+]=2.95\times 106{-3}M

Now we have to calculate the acid dissociation constant.

The equilibrium reaction for dissociation of (weak acid) is,

                        HC_6H_4NO_2\rightleftharpoons C_6H_4NO_2^-+H^+

initially conc.         0.78                0             0

At eqm.               (0.78-x)              x             x  

The expression of acid dissociation constant for acid is:

k_a=\frac{[C_6H_4NO_2^-][H^+]}{[C_6H_4NO_2]}

As, [H^+]=[C_6H_4NO_2^-]=x

So,  x=2.95\times 106{-3}M

Now put all the given values in this formula ,we get:

k_a=\frac{(x)\times (x)}{(0.78-x)}

k_a=\frac{(2.95\times 106{-3})\times (2.95\times 106{-3})}{(0.78-2.95\times 106{-3})}

K_a=1.1\times 10^{-5}

Therefore, the value of acid dissociation constant is, 1.1\times 10^{-5}

7 0
4 years ago
Nuclear reactions are different from chemical reactions, because in nuclear reactions, the transformations between species don't
Lorico [155]
That is true. the nuclei change in nuclear rxns. Chemical rnxs use electrons..
5 0
3 years ago
Read 2 more answers
NEED HELP ASAP WITH THESE QUESTIONS GIVING FAIR AMOUNT OF POINTS IF HELPED WITH ALL QUESTIONS Violet light has a wavelength of 4
scoray [572]

Answer:

a) 7.14e19 Hz

b) 2.298e-27 J

c) 2.793e-19 J; 7.117e9 nm

d) 7.5e14 Hz; 4.96e-19 J

e) 6.2947e-18 J; 31.6 nm

f) 2.21e-22 J

g) 7.1e-19 J; 1.1e15 Hz

h) 3.422e-19 J; 581 nm

i) 4.2e14 Hz

j) 1.92e8 m

k) 7.14e16 Hz; Ultraviolet

Explanation:

Frequency: ν       Wavelength: λ       Energy: E       Speed of light: C (3.00e8)       Planck's Constant: h (6.626e-34)

ν -> λ    λ = C/ν

λ -> ν    ν = C/λ

For either of these equations, wavelength must be converted to meters or nanometers, depending on the equation.

For ν -> λ, after doing the equation, convert the wavelength into nanometers by dividing by 1e-9.

For converting λ -> ν, convert the wavelength into meters by multiplying by 1e-9.

For energy: E = hν = hc/λ

Now that the setup is out of the way:

a) Violet light has a wavelength of 4.20 x 10-12 m. What is the frequency?

λ -> ν    ν = C/λ

\frac{3.00e8}{4.20e-12} = 7.14e19 Hz

b) A photon has a frequency (n) of 3.468 x 106 Hz. Calculate its energy

E = hν = hc/λ

(6.626e-34) (3.468e6) = 2.298e-27 J

c) Calculate the energy (E) and wavelength (l) of a photon of light with a frequency of 4.215 x 1014 Hz.

E = hν = hc/λ

(6.626e-34) (4.215e14) = 2.793e-19 J

ν -> λ    λ = C/ν

\frac{3.00e8}{4.215e14} = 7.117 m

\frac{7.117m}{1}*\frac{1nm}{1e-9m} = 7.117e9 nm

d) Calculate the frequency and the energy of blue light that has a wavelength of 400 nm  (h = 6.62 x 10-34 J-s).

λ -> ν    ν = C/λ

\frac{400 nm}{1} *\frac{1e-9m}{1nm} = 4e-7 m

\frac{3.00e8}{4e-7} = 7.5e14 Hz

E = hν = hc/λ

(6.626e-34) (7.5e14) = 4.96e-19 J

e) Calculate the wavelength and energy of light that has a frequency of 9.5 x 1015 Hz.

ν -> λ    λ = C/ν

\frac{3.00e8}{9.5e15} = 3.16e-8 m

\frac{3.16e-8m}{1}*\frac{1nm}{1e-9m} = 31.6 nm

E = hν = hc/λ

(6.626e-34) (9.5e15) = 6.2947e-18 J

f) A photon of light has a wavelength of 0.090 cm. Calculate its energy.

E = hν = hc/λ

Convert the wavelength from cm to meters:

\frac{0.090cm}{1} *\frac{1m}{100cm} = 9e-4 m

\frac{(6.626e-34)(3.00e8)}{9e-4} = 2.21e-22 J

g) Calculate the energy and frequency of red light having a wavelength of 2.80 x 10-5 cm.

E = hν = hc/λ

Convert the wavelength from cm to meters:

\frac{2.80e-5cm}{1} *\frac{1m}{100cm} = 2.8e-7 m

\frac{(6.626e-34)(3.00e8)}{2.8e-7} = 7.1e-19 J

λ -> ν    ν = C/λ

Convert the wavelength from cm to meters:

\frac{2.80e-5cm}{1} *\frac{1m}{100cm} = 2.8e-7 m

\frac{3.00e8}{2.8e-7} = 1.1e15 Hz

h) Calculate the energy (E) and wavelength (l) of a photon of light with a frequency of 5.165 x 1014 Hz.

E = hν = hc/λ

(6.626e-34) (5.165e14) = 3.422e-19 J

ν -> λ    λ = C/ν

\frac{3.00e8}{5.165e14} = 5.81e-7 m

\frac{5.81e-7m}{1}*\frac{1nm}{1e-9m} = 581 nm

i) The wavelength of green light from a traffic signal is centered at 7.20 x 10-5 cm. Calculate the frequency.

λ -> ν    ν = C/λ

Convert the wavelength from cm to meters:

\frac{7.20e-5 cm}{1} *\frac{1m}{100cm} = 7.2e-7 m

\frac{3.00e8}{7.2e-7} = 4.2e14 Hz

j) If it takes 1.56 seconds for radio waves (which travel at the speed of light) to reach the moon from Earth, how far away is the moon?

  All we want to do here is to convert frequency (speed) to wavelength (distance). This problem requires a bit of thought, but it isn't bad once you realize that frquency is speed and wavelength is distance. It becomes just like the other problems after that. Also, I'll leave this distance in meters, but I think you can figure out how to convert it if it wants it in another unit.

  One second is equal to 1 Hertz, so our frequency is 1.56 Hz.

ν -> λ    λ = C/ν

\frac{3.00e8}{1.56} = 1.92e8 m

  The actual distance from the earth to the moon via google is 3.84e7, but sometimes problems like this will mess with the numbers to make sure that you didn't just look up the answer. I'm still pretty sure that this is right, however.

k) Calculate the frequency of light that has a wavelength of 4.20 x 10-9m. Identify the type of electromagnetic radiation.

First, we convert wavelength to frequency, as normal:

λ -> ν    ν = C/λ

\frac{3.00e8}{4.20e-9} = 7.14e16 Hz

Then we identify the electromagnetic wave type. You can look up a conversion chart for these on google, but since our frequency is in the e15 - e17 range, this light is considered ultraviolet.

5 0
4 years ago
Which organ system carries materials to human tissues?
weqwewe [10]

Answer:

Cardiovascular they carry according to me

7 0
3 years ago
1. Consider the chemical equation. If there are 40 mol of NBr3 and 48 mol
marusya05 [52]

Answer:

NaOH

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2NBr3 + 3NaOH —> N2 + 3NaBr + 3HOBr

The limiting reactant can be obtained as follow:

From the balanced equation above,

2 moles of NBr3 reacted with 3 moles of NaOH.

Therefore, 40 moles of NBr3 will react with = (40 x 3)/2 = 60 moles of NaOH.

From the above calculations,

A higher amount of NaOH i.e 60 moles than what was given from the question i.e 48 moles is required to react completely with 40 moles of NBr3. Therefore, NaOH is the limiting reactant and NBr3 is the excess reactant.

7 0
3 years ago
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