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gizmo_the_mogwai [7]
3 years ago
13

How many moles of hydrogen are in 2.8 moles of caffeine

Chemistry
2 answers:
tekilochka [14]3 years ago
5 0
Recall that a mole is defined as Avogadro's number of particles what the formula of caffeine basically tells us is that every molecule of caffeine you will have 8 atoms of carbon 10 atoms of hydrogen 4 atoms of nitrogen and 2 atoms of oxygen so if we have 0.3 moles of caffeine we will have 4*0.3 moles of nitrogen which is 0.12 and you got the idea
frosja888 [35]3 years ago
5 0

<u>Answer:</u> The moles of hydrogen in given moles of caffeine are 28 moles.

<u>Explanation:</u>

We are given:

Moles of caffeine = 2.8 moles

The chemical formula of caffeine is C_8H_{10}N_4O_2

In 1 mole of caffeine, 8 moles of carbon atoms, 10 moles of hydrogen atoms, 4 moles of nitrogen atoms and 2 moles of oxygen atoms are present.

So, in 2.8 moles of caffeine, moles of hydrogen atoms present will be (10\times 2.8)=28 moles

Hence, the moles of hydrogen in given moles of caffeine are 28 moles.

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In a certain electrolysis experiment, 1.24 g of Ag were deposited in one cell (containing an aqueous AgNO3 solution), while 0.65
eduard

Answer:

The correct answer is 169.56 g/mol.

Explanation:

Based on the given information, the mass of Ag deposited is 1.24 g, and the mass of unknown metal X deposited in another cell is 0.650 g. The number of moles of electrons can be determined as,

= 1.24 g Ag * 1mol Ag/107.87 g/mol Ag * 1 mol electron/1 mol Ag ( the molecular mass of Ag is 107.87 g/mol)

= 0.0115 mole of electron

The half cell reaction for the metal X is,  

X^3+ (aq) + 3e- = X (s)

From the reaction, it came out that 3 faraday will reduce one mole of X^3+.  

The molar mass of X will be,  

= 0.650 g/0.0115 *3 mol electron/1 mol

= 56.52 * 3

= 169.56 g/mol

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3 years ago
Describe heat transfer of Getting hot sitting outside in the sun.
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In testing the effectiveness of an antacid compound, 20.0g of Hydrochloric Acid is mixed with 28.0g of Magnesium Hydroxide. Will
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Answer:

Base Mg(OH)2 does neutralise the acid and is 12g in excess.

Explanation:

2HCL +Mg(OH)2 -> MgCl2 + 2H20

2 * 36.458 g of HCL react with  58.319 g of  Mg(OH)2 to neutralise it.

72.916 HCl reacts with  58.319 g of the base.

So 20 g HCl reacts with  (58.319/72.916) * 20 = 16g.

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3 years ago
1. Using the Slater rule, determine the effective nuclear charge of platinum.
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Answer:

Z* = 3.55

Explanation:

Slater rule says that:

Z*= Z - S

Z* be the nuclear effective charge

Z is the nuclear charge

S is the shielding constant

First we write the electronic configuration of platinum:1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6} 4f^{14} 5d^{9} 6s^{1}

The first Slater rule says that we need to group:

(1s^{2}) (2s, 2p)^{8} (3s, 3p)^{8} (3d^{10}) (4s, 4p)^{8} (4d^{10}) (5s, 5p)^{8} (4f^{14}) (5d^{9}) (6s^{1})

The second rule says that the electrons to the right are not shielding, but we are going to solve the exercise for the last level (6s), so we don't have electrons to the right.

For the third rule we have two considerations, if is ns or np and if is nd or nf:

For our case, we have an electro that is in ns, so the rule says that

-electrons within same group shield 0.35, except the 1s which shield 0.30

-electrons within the n-1 group shield 0.85

-electrons within the n-2 or lower groups shield 1.00

Now we can proceed with the calculation:

The first consideration in the third rule does not apply as we only have one electron on this level.

The second consideration will be as follow for the level 5, where we have 17 electrons.

Finally the third consideration will be for levels 1, 2, 3 and 4, where we have 14 for 4f, 10 for 4d, 8 for 4s and 4p, 10 for 3d, 8 for 3s and 3p, 8 for 2s and 2p and finally 2 for 1s, which gives 60 electrons.

So the result for S=(60*1.00 + 17*0.85) = 74.45

And the equation is: Z* = 78 - 74.45

So Z* = 3.55

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