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hjlf
2 years ago
13

Need help on this question ASAP pleasee and thanks!

Mathematics
1 answer:
ollegr [7]2 years ago
5 0

Answer:

Sorry but I don't know the answer too this question

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Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel
timama [110]

Answer:

\displaystyle A=\frac{1}{192}

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

P=4x+3y

We know the total fencing is 1/2 miles long, thus

\displaystyle 4x+3y=\frac{1}{2}

Solving for x

\displaystyle x=\frac{\frac{1}{2}-3y}{4}

The total area of the pasture is

A=x.y

Substituting x

\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y

\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}

Differentiating with respect to y

\displaystyle A'=\frac{\frac{1}{2}-6y}{4}

Equate to 0

\displaystyle \frac{\frac{1}{2}-6y}{4}=0

Solving for y

\displaystyle y=\frac{1}{12}

And also

\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}

Compute the second derivative

\displaystyle A''=-\frac{3}{2}.

Since it's always negative, the point is a maximum

Thus, the maximum area is

\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}

6 0
3 years ago
Lukas graphed the system of equations shown.
vampirchik [111]

The system of equations 2x + 3y = 2 and y = (1/2)x + 3 have solutions at x = -2 and y = 2

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

From the system of equations 2x + 3y = 2 and y = (1/2)x + 3, the graph of the equation shows that the solution is at x = -2 and y = 2

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
Which line on the graph represents the equation y + 4 = -2x/3
Korolek [52]

Answer:

The answer is line D

Step-by-step explanation:

3 0
3 years ago
2 find the probability of getting a sum 9 when two dice are thrown simultaneously.
Cloud [144]

Answer:

The answer is 11.1

Step-by-step explanation:

First you need to figure out what all of the possible combinations of the two dice being thrown then divide it by the number of faces on both dice and you get your probability.

3 0
3 years ago
Y=3x-2
Inessa [10]

Answer:

a) (x,y) = (3, 7) is a solution of the linear equation.

b) The rate of change of the equation is 3.

c) The y-intercept of the equation is -2.

d) <em>Jayne is working in the grocery one day, according to her calculations, renting the lot costs 2 dollars per day and she could earn 3 dollars per hour by selling pastries. How much money does she earn after working 8 hours?</em>

Step-by-step explanation:

a) If (x,y) = (3, 7) is a solution of the linear equation, then f(3) = 7. If x = 3, then the function evaluated at this value is:

y  = 3\cdot (3) -2

y = 7

Hence, (x,y) = (3, 7) is a solution of the linear equation.

b) The rate of change of the equation is represented by the slope of the function, which is the constant that multiplies the indepedent variable (x). Hence, the rate of change of the equation is 3.

c) The y-intercept of the equation is the only constant of the equation. Hence, the y-intercept of the equation is -2.

d) A real-world scenario would be the following: <em>Jayne is working in the grocery one day, according to her calculations, renting the lot costs 2 dollars per day and she could earn 3 dollars per hour by selling pastries. How much money does she earn after working 8 hours?</em>

7 0
3 years ago
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