he memory protection requirement must be satisfied by the operating system rather than the processor. True False

____________ describes all the communication channels that allow community-based input, interaction, content-sharing and collabo

vladimir1956 [14]

Answer:

Social media.

Explanation:

The social media is an online platform that provides its users with the web application interface for easy communication. Since it is online, the user must subscribe to a ISP service, create an account on the social media website, and optionally download it's application on the device for easy access.

User accounts are secured with a username and password. The user on the site can share graphic, video, audio and text content, interact with friends etc.

7 0

4 years ago

BlockPy: #38.2) While Input Use a while loop to repeatedly take input from the user and print whatever they type in. When the us

BARSIC [14]

Answer:

strr=input("please enter something: ")

while strr is not "":

print(strr)

strr=input("please enter something: ")

Explanation:

whenever the user will enter an empty string the loop will terminate

8 0

4 years ago

Find a quote that you like. Store the quote in a variable, with an appropriate introduction such as "Ken Thompson once said, 'On

pishuonlain [190]

Answer:

The program to this question as follows:

Program:

quote="You can always edit a bad page. You can’t edit a blank page."

name="Jodi Picoult"

print("Quote:\n",quote)

print ('\t\t\t\t\t\t\t',"Author name-", name)

Output:

Quote:

You can always edit a bad page. You can’t edit a blank page.

Author name- Jodi Picoult

Explanation:

In the above python code, two variable "quote and name" is defined, in which variable both variable holds some string value.

In the next line, the print function is defined, that first print "Quote" as a message, and for line breaking "\n" is used, then print quote variable value.

In the last step, first, we use "\t" for line spacing then message "Author name-", and then name variable value.

7 0

3 years ago

doubleUp Write a method doubleUp that doubles the size of a list of integers by doubling-up each element in the list. Assume the

Maslowich

Answer:

The solution in Python is as follows:

class myClass:

def doubleUp(self,myList):

myList[:0] = myList[::2] = myList[1::2] = myList[:]

mylist = [1, 3, 2, 7]

list = myClass()

list.doubleUp(mylist)

print(mylist)

Explanation:

To create a method in Python, the first step is to create a Class.

This is done in the following line:

class myClass:

Then this line defines the method

def doubleUp(self,myList):

This line duplicates the elements of the list

myList[:0] = myList[::2] = myList[1::2] = myList[:]

This defines the list

mylist = [1, 3, 2, 7]

This creates an instance of the class

list = myClass()

This passes the list to the doubleUp method

list.doubleUp(mylist)

This prints the duplicated list

print(mylist)

4 0

3 years ago

5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S

Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0

3 years ago