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2 years ago

As an object slides across a rough horizontal

Physics

1 answer:

tiny-mole [99]2 years ago

6 0

When the object slides across the rough surface some of its potential energy will be lost to friction.

<h3>Conservation of mechanical energy</h3>

The law of conservation of mechanical energy states that the total mechanical energy of an isolated system is always constant.

M.A = P.E + K.E

When the object slides across the rough surface, some of the potential energy of the object will be converted into kinetic energy while the remaining potential energy will be converted into thermal energy due to frictional force of the rough surface.

P.E = K.E + thermal energy

Learn more about conservation of energy here: brainly.com/question/166559

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The amount of energy to change a gram of a liquid to a gas at the boiling point describes which of the following

Butoxors [25]

C is correct... .. :)

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3 years ago

Help me to solve it . It’s urgent

Artist 52 [7]

Answer: 0°

Explanation:

Step 1: Squaring the given equation and simplifying it

Let θ be the angle between a and b.

Given: a+b=c

Squaring on both sides:

... (a+b) . (a+b) = c.c

> |a|² + |b|² + 2(a.b) = |c|²

> |a|² + |b|² + 2|a| |b| cos 0 = |c|²

a.b = |a| |b| cos 0]

We are also given;

|a+|b| = |c|

Squaring above equation

> |a|² + |b|² + 2|a| |b| = |c|²

Step 2: Comparing the equations:

Comparing eq( insert: small n)(1) and (2)

We get, cos 0 = 1

> 0 = 0°

Final answer: 0°

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7 0

3 years ago

A straight wire segment 5 m long makes an angle of 30° with a uniform magnetic field of 0.37 T. Find the magnitude of the force

SIZIF [17.4K]

Answer:

The magnitude of the force on the wire is 2.68 N.

Explanation:

Given that,

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We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :

$F=BIL\ \sin\theta\\\\F=0.37\ T\times 2.9\ A\times 5\ m\times \ \sin(30)\\\\F=2.68\ N$

So, the magnitude of the force on the wire is 2.68 N. Hence, this is the required solution.

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3 years ago

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B, the acceleration due to gravity is 9.8m/s/s regardless of mass

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3 years ago

A solid ball is released from rest and slides down a hillside that slopes downward at an angle 51.0 ∘ from the horizontal. what

Romashka [77]

In order for the object not to slip, the component of the weight parallel to the surface must be equal to the frictional force (which acts in the opposite direction):
$F_{//}= F_a$

The parallel component of the weight is:
$F_{//} = mg \sin \alpha$
where m is the object mass and $\alpha$ is the angle of the inclined plane.

The frictional force is
$F_a = \mu m g \cos \alpha$
where $\mu$ is the coefficient of static friction.

Equalizing the two forces, we have
$mg \sin \alpha = \mu m g \cos \alpha$
from which we find
$\mu = \tan \alpha$

and so, in our problem the coefficient of static friction must be
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3 years ago