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3 years ago

Fiona drives 18 meters east and 24 meters south. What is the magnitude of her displacement?

Physics

1 answer:

alexira [117]3 years ago

3 0

Answer:

30.0 m

Explanation:

Displacement is the distance between her initial position and her final position.

In this case, it's the hypotenuse of the right triangle formed by the east and south distances.

x² = (18)² + (24)²

x = 30.0

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A block slides forward 4.73 m while being pulled back by a 39.7 N force at 142° from the direction of motion. How much work does

lubasha [3.4K]

Answer:

work done by the force, W = -147.97 J

Given:

displacement of the box, s = 4.73 m

angle between force and displacement, $\theta = 142^{\circ}$

Force, F = 39.7 N

Solution:

Work done by the force can be expressed as the dot product of Force, F and displacement 's' is given by:

W = Fscos $\theta$

W = 39.7 $\times 4.73\times cos142^{\circ}$

W = -147.97 J

where negative sign indicates that work is done on the block

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3 years ago

What is the speed of a bobsled whose distance-time graph indicates that it traveled 117m in 25s

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2 years ago

Automobile air bags use the decomposition of sodium azide as their sources of gas for rapid inflation, represented in the reacti

NeTakaya

Answer : The mass of $NaN_3$ required is 71.175 grams.

Explanation :

To calculate the moles of nitrogen gas, we use the equation given by ideal gas :

PV = nRT

where,

P = Pressure of nitrogen gas = 763 torr

V = Volume of the nitrogen gas = 40.0 L

n = number of moles of gas = ?

R = Gas constant = $62.364\text{ L.torr }mol^{-1}K^{-1}$

T = Temperature of helium gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$763torr\times 40.0L=n\times 62.364\text{ L.torr }mol^{-1}K^{-1}\times 298K\\\\n=1.642mol$

Now we have to calculate the moles of $NaN_3$ .

The balanced chemical reaction is:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

From the balanced chemical reaction, we conclude that

As, 3 moles of $N_2$ produced from 2 moles $NaN_3$

So, 1.642 moles of $N_2$ produced from $\frac{2}{3}\times 1.642=1.095$ moles $NaN_3$

Now we have to calculate the mass of $NaN_3$ .

Molar mass of $NaN_3$ = 65 g/mol

$\text{Mass of }NaN_3=\text{Moles of }NaN_3\times \text{Molar mass of }NaN_3$

$\text{Mass of }NaN_3=1.095mole\times 65g/mole=71.175g$

Therefore, the mass of $NaN_3$ required is 71.175 grams.

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3 years ago

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SVETLANKA909090 [29]

Answer:

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Explanation:

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