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3 years ago

Fiona drives 18 meters east and 24 meters south. What is the magnitude of her displacement?

Physics

1 answer:

alexira [117]3 years ago

3 0

Answer:

30.0 m

Explanation:

Displacement is the distance between her initial position and her final position.

In this case, it's the hypotenuse of the right triangle formed by the east and south distances.

x² = (18)² + (24)²

x = 30.0

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Do you think an observer on another planet in the solar system might see eclipses

artcher [175]

Answer:

Yes

Explanation:

Eclipses: Eclipses are also known as game of shadows where one object comes between the star(light source) and another object in a straight line such that the shadow of one object falls on other object. This can occur when the apparent size of the star and the object is almost same.

Talking about the Earth, the geometry is such that the Moon and the Sun are of same apparent size as seen from the Earth. Thus Lunar and Solar eclipse can be seen from the Earth. If we were to go on any other planet the same phenomenon can be seen provided the apparent size of moon and the Sun from that planet is same.

We have seen and recorded many such eclipses on Jupiter. These are from the perspective of Earth. When the moons of Jupiter comes exactly between the Sun and Jupiter the shadow of moon will fall on Jupiter. The places where the shadow falls, one will see a solar eclipse.

8 0

3 years ago

It requires 3480 J to move a 675 N object how far?

goblinko [34]

5.16 meters!!!!!!!!!!!!!!!!!!!!

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3 years ago

Two loudspeakers are placed next to each other and driven by the same source at 500 Hz. A listener is positioned in front of the

stellarik [79]

To solve this problem we will apply the concepts related to wavelength as the rate of change of the speed of the wave over the frequency. Mathematically this is

$\lambda = \frac{v}{f}$

Here,

v = Wave velocity

f = Frequency,

Replacing with our values we have that,

$\lambda = \frac{340}{500}$

\lambda = 0.68m

The distance to move one speaker is half this

$\lambda/2 = 0.34m$

Therefore the minimum distance will be 0.34m

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3 years ago

¿Por qué los mensajes llegan en forma inmediata de un celular a otro?

KATRIN_1 [288]

Porque el internet ayuda a la rapidez del mensaje.

7 0

3 years ago

Two loudspeakers in a 20c room emit 686 hz sound waves along the x-axis.a. if the speakers are in phase, what is the smallest di

jeyben [28]

<u>Answer :</u>

(a) d = 0.25 m

(b) d = 0.5 m

<u>Explanation :</u>

It is given that,

Frequency of sound waves, f = 686 Hz

Speed of sound wave at $20^0\ C$ is, v = 343 m/s

(1) Perfectly destructive interference occurs when the path difference is half integral multiple of wavelength i.e.

$d=\dfrac{\lambda}{2}$ ........(1)

Velocity of sound wave is given by :

$v=f\times \lambda$

$d=\dfrac{v}{2f}$

$d=\dfrac{343\ m/s}{2\times 686\ Hz}$

$d=0.25\ m$

Hence, when the speakers are in phase the smallest distance between the speakers for which the interference of the sound waves is perfectly destructive is 0.25 m.

(2) For constructive interference, the path difference is integral multiple of wavelengths i.e.

$d=n\lambda$ ( n = integers )

Let n = 1

So, $d=\dfrac{v}{f}$

$d=\dfrac{343\ m/s}{686\ Hz}$

$d=0.5\ m$

Hence, the smallest distance between the speakers for which the interference of the sound waves is maximum constructive is 0.5 m.

4 0

3 years ago

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