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damaskus [11]
3 years ago
6

Suggest three properties which magnesium chloride has because it is an ionic compound

Physics
1 answer:
Elza [17]3 years ago
3 0
MG^2CL^-2 THIS IS THE FORMULA
You might be interested in
Kinetic Energy RE-
tatiyna

Answer:

1) The potential energy, P.E  = 4527.6 J

2) The mass, m = 1.28 kg

3) The height of the bell, h = 4.31 m

4)  The kinetic energy, K.E = 385 J

5) The velocity of the car, V = 22.53 m/s

6) The mass of the car,  m = 17.59 kg

Explanation:

1) The height of the hill, h = 21 m

The carriage with a baby has mass of, m = 22 kg

The potential energy,

                             P.E = mgh

                                   = 22 x 9.8 x 21

                                  = 4527.6 J

2) The height of the platform, h = 20 m

The P.E of the cinder block, P.E = 250 J

The mass,

                                m = P.E / gh

                                     = 250 / (9.8 x 20)

                                    = 1.28 kg

3) The mass of the bell, m = 18 kg

The P.E of the bell, P.E = 760 J

The height of the bell,

                            h = P.E/mg

                               = 760 / 18 x 9.8

                               = 4.31 m

4) The mass of the runner, m = 55 kg

The velocity of the runner, v = 14 m/s

The kinetic energy,

                              K.E = ½ mv²

                                     = ½ x 55 x 14

                                     = 385 J

5)The kinetic energy of the car, K.E = 69,759 J

The mass of the car, m = 275 kg

The velocity of the car,

                                 V = √(2K.E/m)

                                  V = √( 2 x 69759 / 275)

                                      = 22.53 m/s

6) The velocity of the car, v = 38 m/s

The kinetic energy of the car, K.E = 12700 J

The mass of the car,

                                m = 2 K.E/ v²

                                     = 2 x 12700 / 38²      

                                 m = 17.59 kg

8 0
3 years ago
1
Luda [366]

Explanation:

heat engine is correct answer

3 0
3 years ago
Read 2 more answers
The theory of light has been expounded differently by scientists in different periods of time. What is an important reason for t
wlad13 [49]
Technological advances clearly.

Theories change due to other peoples view on the matter and how they experiment with it, but Technology advancements are the greatest factor of all. I mean seriously, we wouldn't know of cells before the microscope and when they first invented it, it advanced further and now we can see things on a whole deeper lever.
8 0
3 years ago
A satellite is in circular orbit at an altitude of 1500 km above the surface of a nonrotating planet with an orbital speed of 9.
Ksju [112]

To solve this problem we will use the Newtonian theory about the speed of a body in space for which the speed of a body in the orbit of a planet is summarized as:

v =  \sqrt{\frac{2GM}{R}}

Where,

G = Gravitational Universal Constant

M = Mass of Planet

r = Radius of the planet ('h' would be the orbit from the surface)

The escape velocity is

v = 14.9km/h = 14900m/s

Through this equation we can find the mass of the Planet in function of the distance, therefore

M = \frac{v^2R}{2G}

M = \frac{14900^2R}{2(6.67*10^{-11})}

M = 16.64*10^{17}R

The orbital velocity is

v_o = \sqrt{\frac{GM}{R+h}}

9200^2 = \frac{(6.67*10^{-11})(16.64*10^{17})R}{R+1500*10^3}

11.1*10^7R = (R+15000*10^3)(9200)^2

2.64*10^7R = 12.69*10^{13}

R = 4.81*10^6m

The time period of revolution is,

T = \frac{2\pi(R+h)}{v_o}

T = \frac{2\pi(4.81*10^6+1.5*10^6)}{9200}

T = 4307s

T = 72min = 1hour12min

Therefore the orbital period of the satellite is closes to 1 hour and 12 min

3 0
3 years ago
An airplane flies in a loop (a circular path in a vertical plane) of radius 160 m . The pilot's head always points toward the ce
notka56 [123]

Answer:

a) 39.6 m/s b) 4123 N

Explanation:

a) At the top of the loop, all of the forces point downwards (force of gravity and normal force).

Fnet=ma

ma=m(v^2/R) (centripetal acceleration)

mg=m(v^2/R)

m cancels out (this is why pilot feels weightless) so,

g=(v^2/R)

9.8 m/s^2 = v^2/160 m

v^2=1568 m^2/s^2

v=39.6 m/s

b) At the bottom of the loop, the normal force and the force of gravity point in opposite directions. The normal force is the weight felt.

Convert 300 km/hr to m/s

300 km/hr=83.3 m/s

Convert pilot's weight into mass:

760 N = 77.55 kg

Fnet=ma

n-mg=m(v^2/R)

n=(77.55 kg)(((83.3 m/s)^2)/160 m)+(77.55 kg)(9.8 m/s^2)

n=3363.2 N+760 N=4123 N

5 0
3 years ago
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