1. A block of aluminum occupies

The phase velocity of transverse waves in a crystal of atomic separation a is given byy = csin(ka/2) pka/2 1. What is the disper

damaskus [11]

Answer:

a

e(k) = \frac{2a}{c} * sin (\frac{k*a}{2} )

b

G_{v} = \frac{d e(k ) }{dk } = \frac{a^2}{c} * cos (\frac{k* a}{2} )

Explanation:

From the question we are told that

The velocity of transverse waves in a crystal of atomic separation is

$b_y = c \frac{sin (\frac{k*a}{2} )}{\frac{k*a}{2} }$

Generally the dispersion relation is mathematically represented as

$e(k) = b_y * k$

=> $e(k) = c \frac{sin(\frac{k*a}{2} ) }{ \frac{k*a}{2} } * k$

=> $e(k) = c * \frac{sin (\frac{k_a}{2} )}{ \frac{a}{2} }$

=> $e(k) = \frac{2a}{c} * sin (\frac{k*a}{2} )$

Generally the group velocity is mathematically represented as

$G_{v} = \frac{d e(k ) }{dk } = \frac{a^2}{c} * cos (\frac{k* a}{2} )$

7 0

3 years ago

Given that the wavelengths of visible light range from 400 nm to 700 nm, what is the highest frequency of visible light? (ccc =

enot [183]

7.5 × 10¹⁴ Hz is the highest frequency of visible light when wavelengths of visible light range from 400 nm to 700 nm.

The distance a wave travels in one unit of time is known as the wave speed (v).Taking into account that the wave travels one wavelength in one interval,

v=λ/T

Given that T = 1/f, we can write the equation above as,

V = f λ

Given data:

Minimum wavelength of visible light = 400 nm = 4 × 10⁻⁷ m

Speed of light = 3 × 10⁸ m/s

Frequency = c/λ = 3 × 10⁸ / 4 × 10⁻⁷

= 7.5 × 10¹⁴ Hz

To learn more about Frequency: brainly.com/question/16200748

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4 0

1 year ago

Meteoroid is the term used to describe a solid particle that

LuckyWell [14K]

Is drifting around in space

5 0

3 years ago

One speed skater starts across a frozen lake at an average speed of 8 m/s. Ten seconds later, a second speed skater starts from

Luba_88 [7]

Answer:

40 s

Explanation:

After 10 seconds, the first skater would have a 8m/s * 10s = 80 m head start

Let t be the number of seconds after the second skater starts will the second skater overtake the first skater

The distance traveled by the first skater after t seconds is

$s_1 = v_1t = 8t$

Similarly the distance traveled by the 2nd skater after t seconds is

$s_2 = v_2t = 10t$

Since the 2nd skater catches up to the 1st one after 80 m behind, the distance traveled by the 2nd one must be 80m greater than the distance of the 1st skater

$s_2 = s_1 + 80$