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Anastaziya [24]
3 years ago
7

One type of sunburn occurs on exposure to UV light with a wavelength in the vicinity of 325 nm. What is the energy of a mole of

these photons?
Physics
1 answer:
andrew11 [14]3 years ago
3 0

Answer: Energy of a mole of these photons is 0.368\times 10^6Joules  

Explanation:

The relationship between wavelength and energy of the wave for 1 mole follows the equation:

E=\frac{Nhc}{\lambda}

E= energy

N= avogadros number =6.023\times 10^{23}

\lambda = wavelength of the wave  =325\times 10^{-9}m    1nm=10^{-9}m

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

E=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8m/s}{325\times 10^{-9}m}

E=0.368\times 10^6Joules  

Thus the energy of a mole of these photons is 0.368\times 10^6Joules  

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Assume a rectangular strip of a material with an electron density of n=5.8x1020 cm-3. The strip is 8 mm wide and 0.8 mm thick an
vampirchik [111]

Answer: I = 111.69 pA

Explanation: The hall effect is all about the fact that when a semiconductor is placed perpendicularly to a magnetic field, a voltage is generated which could be measured at right angle to the current path. This voltage is known as the hall voltage.

The hall voltage of a semiconductor sensor is given below as

V = I×B/qnd

Where V = hall voltage = 1.5mV =1.5/1000=0.0015V

I = current =?,

n= concentration of charge (electron density) = 5.8×10^20cm^-3 = 5.8×10^20/(100)³ = 5.8×10^14 m^-3

q = magnitude of an electronic charge=1.609×10^-19c

B = strength of magnetic field = 5T

d = thickness of sensor = 0.8mm = 0.0008m

By slotting in the parameters, we have that

0.0015 = I × 5/5.8×10^14 × 1.609×10^-19×0.0008

0.0015 = I×5/7.446×10^-8

I = (0.0015 × 7.446×10^-8)/5

I = 111.69*10^(-12)

I = 111.69 pA

3 0
2 years ago
When an 8 V battery is connected to a resistor, a 2 A current flows in the resistor. What is the resistor's value?
Vinvika [58]

Answer:

B

Explanation:

V=IR    I= curren V=volt R=resistor

8=2.R   8/2=R R=4

5 0
3 years ago
A disc is thrown through the air for 1.5 min with a power output of 12.5 W. How much work is done when throwing the disc?
klasskru [66]

Answer:

work = 1125 [J]

Explanation:

To solve this problem we must remember the definition of power, which is defined as the relationship between work and time. The power can be calculated using the following equation:

Power = work/time

Power = 12.5 [w]

work = joules [J]

time = 1.5 [min] = 90 [s]

work = 12.5*90

work = 1125 [J]

7 0
3 years ago
It's a duty of the AHJ to
sammy [17]

The duty of the AHJ is to: (C). review installation designs and determine if they fall under Code jurisdiction

<h3>Meaning of AHJ</h3>

AHJ can be defined as that means Authority Having Jurisdiction

AHJ can be defined as an organization, office, or individual that are responsible for the issuance of permits, enforcing the requirements of a code or standard and  approving materials or a procedure.

In conclusion, The role of the AHJ are outlined in the paragraph above.

Learn more about Jurisdiction: brainly.com/question/10377896

#SPJ1

7 0
1 year ago
Your shopping cart has a mass of 65 kilograms, In order to accelerate the shopping cart down an aisle at 0.3 m/sec2, what force
garri49 [273]
Remember Newton's second law: F=ma

to get the force in newtons, mass should be in kg and acceleration in m/s^2

conveniently, we don't need to convert units

we just need to multiply the two to get the force

65* 0.3 = 19.5 kg m/s^2 or N

if significant digit is an issue, the least number if sig figs is 1 so the answer would be 20 N
4 0
2 years ago
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