9514 1404 393
Answer:
34.5 square meters
Step-by-step explanation:
We assume you want to find the area of the shaded region. (The actual question is not visible here.)
The area of the triangle (including the rectangle) is given by the formula ...
A = 1/2bh
The figure shows the base of the triangle is 11 m, and the height is 1+5+3 = 9 m. So, the triangle area is ...
A = (1/2)(11 m)(9 m) = 49.5 m^2
The rectangle area is the product of its length and width:
A = LW
The figure shows the rectangle is 5 m high and 3 m wide, so its area is ...
A = (5 m)(3 m) = 15 m^2
The shaded area is the difference between the triangle area and the rectangle area:
shaded area = 49.5 m^2 - 15 m^2 = 34.5 m^2
The shaded region has an area of 34.5 square meters.
First off both triangles form a 90° angle there both congruent. you can tell they form a 90° angle because of square box
Tangent = opposite / adjacent
In the diagram:
TQ is the short leg or the opposite
QR is the long leg or the adjacent
TR is the hypotenuse. TS is part of the hypotenuse.
Tan(QTR) = TQ / QR
TS = 1 ; TQ = TS so, TQ = 1
Tan(QTR) = 1/QR
I think the answer is C.RQ
Hey there! :D
So for this problem, we would do 20+9 x 40 + 7 which equals 1,363.
Hope it helps! :D