Let's assume
number of small notebooks =x
number of large notebooks =y
we are given
total number of notebooks =31
so, we get

now, we can solve for y

we have
Small notebooks cost $3.50 and large notebooks cost $5.00
she has $134 to spend
so, we get

now, we can plug y





now, we can find y


so,
number of small notebooks is 14
number of large notebooks is 17.............Answer
Answer: Smaller number = 6
Larger number = 20
Step-by-step explanation:
Let the smaller number be x.
Let the larger number be y.
Three times a larger number is 30 more than 5 times a smaller number. This will be:
3 × y = (5 × x) + 30
3y = 5x + 30 ...... i
The sum of the larger number and 5 times the smaller number is 50. This will be:
y + 5x = 50 ...... ii
From equation ii
y + 5x = 50.
y = 50 - 5x ...... iii
Put the value of y = 50 - 5x into equation i
3y = 5x + 30
3(50 - 5x) = 5x + 30
150 - 15x = 5x + 30
150 - 30 = 5x + 15x
120 = 20x
x = 120/20
x = 6
The smaller number is 6
Note that y + 5x = 50
y + 5(6) = 50
y + 30 = 50
y = 50 - 30
y = 20
The bigger number is 20
Answer:
The cost of one hot dog is $2.50
Step-by-step explanation:
You need to subtract $3.20 from $18.20 to get $15.00. Then you need to divide $15.00 by 6 to get $2.50.
E = amount she put for Education
CD = amount she put for a Certificate of Deposit.
so, whatever those amounts are, we know that all she got is 70,000 bucks total, so
E + CD = 70000.
how much is three times the CD? well, 3*CD or 3CD.
how much is 10,000 more than that? well 3CD + 10000.
since we know that the amount on Education was 10000 more than three times the CD, then
E = 3CD + 10000.

how much was it invested in the CD? well, CD = 70000 - E.
Answer:

or

Step-by-step explanation:
Rather than solving this question in a more complex method by directly using the product rule and quotient rule, it can first be considered to perform some algebraic manipulation (index laws) to simplify the expression before taking the derivative.

Now, the derivative of the function can be calculated simply by only using the power rule, which yields
