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icang [17]
2 years ago
11

(3x +4y)2 is equal to

Mathematics
2 answers:
SCORPION-xisa [38]2 years ago
5 0

Answer:

9x² + 24xy + 16y²

Step-by-step explanation:

(3x + 4y)²

= (3x + 4y)(3x + 4y)

each term in the second factor is multiplied by each term in the first factor.

3x(3x + 4y) + 4y(3x + 4y) ← distribute both parenthesis

= 9x² + 12xy + 12xy + 16y² ← collect like terms

= 9x² + 24xy + 16y²

Nikolay [14]2 years ago
4 0

Answer: 6x + 8y

Hope this helps!

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Nuetrik [128]

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

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Now we proceed to factor the formula:

y = x^{5}-27\cdot x^{2}

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Please notice that x^{2}+3\cdot x + 9 have two complex roots.

y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}  \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3}  \right)\cdot (x-3)

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

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babunello [35]

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6 0
3 years ago
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