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ArbitrLikvidat [17]
3 years ago
8

PLSSSS HELP IF YOU TURLY KNOW THISS

Biology
2 answers:
Verizon [17]3 years ago
5 0

Answer:THE ANSWER IS=

C-PERSONA

drek231 [11]3 years ago
3 0
The answer is persona
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According to selye (1956, 1976), the _____ phase of the general adaptation syndrome is responsible for the person making efforts
STALIN [3.7K]
<span>According to Selye (1956, 1976), the resistance  phase of the general adaptation syndrome is responsible for the person making efforts to cope with the threat.</span>
There are three phases in the <span>Hans Selye's General Adaptation Syndrome (GAS). The first one is the Alarm (</span>organism becomes mobilized to meet the threat) . The second is Resistance, and the third is the Exhaustion (it occurs
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3 years ago
Identify the respiration system of amoeba​
Arturiano [62]

Explanation:

In amoeba respiration takes place through its cell membrane also called the plasma membrane. Amoeba gets oxygen gas dissolved in surrounding water through its plasma membrane by the process of diffusion. The oxygen gas diffused inside the body is used up by the amoeba. In the body, the oxygen gas absorbed is used to break down the complex food material into simple molecules. During these metabolic reactions in the body of amoeba, the oxygen gas is converted into carbon dioxide gas. The carbon dioxide gas is also liberated in the surrounding water through the same process of diffusion.

Since amoeba needs oxygen for respiration, the type of respiration is aerobic respiration.

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3 years ago
Airplanes reach cruising altitudes at the lower part of the Earth's stratosphere. This portion of the atmosphere is made up most
Lerok [7]

Answer:

The stratosphere is a layer of Earth's atmosphere. ... The troposphere, the lowest layer, is right below the stratosphere. ... Because of this, jet aircraft and weather balloons reach their maximum operational altitudes within the stratosphere. ... from the bottom of the stratosphere up to altitudes of 40 or 50 km (25 to 31 miles).

Explanation:

6 0
3 years ago
What is the average atomic mass of a sample that has two isotopes, one with a mass of 21 amu at 62% abundance and another with a
motikmotik

Answer:

Average atomic mass = 21.38 amu.

Explanation:

Given data:

Mass of first isotope = 21 amu

Abundance of first isotope = 62%

Mass of second isotope = 22 amu

Abundance of second isotope = 38%

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (62×21)+(38×22) /100

Average atomic mass =  1302 +836 / 100

Average atomic mass = 2138 / 100

Average atomic mass = 21.38 amu.

3 0
3 years ago
PLEASE HELP
Nikitich [7]

Step- by - step - explaination
7 0
3 years ago
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