Question

A sequence starts from -2. The term to term rule is 'square and subtract 3' find the first six numbers of the sequence

Answer 1

Answer:

The first six numbers are $-2,1,-2,1,-2,1$

Step-by-step explanation:

First term is $-2$

The term to term rule is 'square and subtract $3$'

Second term$=(-2)^{2} -3=1$

Third term$=(1)^{2} -3=-2$

Fourth term$=(-2)^{2} -3=1$

Fifth term$=(1)^{2} -3=-2$

Sixth term$=(-2)^{2} -3=1$

The first six numbers are $-2,1,-2,1,-2,1$