If you decreased the volume of a sample of gas by a factor of three while maintaining a constant pressure, how would the absolute temperature of the gas be affected?
✔ it would decrease threefold
A gas at 300 K and 4.0 atm is moved to a new location with a temperature of 250 K. The volume changes from 5.5 L to 2.0 L. What is the pressure of the gas at the new location?
✔ 9.2 atm
What is the partial pressure of 0.50 mol Ne gas combined with 1.20 mol Kr gas at a final pressure of 730 torr?
✔ 215 torr
I think its c but im not entirely sure
Answer: 92mg of ethyl alcohol
2 milli molar of ethyl alcohol means 2 milli mole glucose for 1 liter of water. Since we want to make 1L of solution, then the amount of ethyl alcohol needed is: 2 milli mole/l x 1l= = 2 x 10^-3 mole
Ethyl alcohol molecular weight is 46g/mole, then 2 mili mole of glucose is= 2x 10^-3 mole x 46 grams/mole= 92 grams x 10^-3= 92mg
The total change in internal energy would simply be
calculated using the formula:
ΔU = -P (V2 – V1) + ΔH
where ΔU is the change in internal energy; P is constant
pressure = 30 atm = 3,039,750 Pa; V2 is final volume = 2 L = 0.002 m^3; V1 is
initial volume = 7.20 L = 0.0072 m^3; while ΔH is the heat = -74,400 J (heat
released so negative)
Therefore:
ΔU =-3,039,750 Pa * (0.002 m^3 - 0.0072 m^3) + (- 74,400
J)
<span>ΔU = - 58,593.3 J = - 58.6 kJ</span>
Answer:
THE PARTIAL PRESSURE OF OXYGEN GAS IN THE CONTAINER IS 92.67kPa WHICH IS OPTION B.
Explanation:
To calculate the partial pressure of oxygen gas collected over water, we use
Ptotal = Poxygen + P water
It is worthy to note that when oxygen is collected over water, it is mixed with water vapor and the total pressure in the container will be the sum of the pressure exerted by the oxygen gas and that of the water vapor at that given temperature.
At 20 C, the vapor pressure of water as given in the question is 2.33 kPa.
Using the above formula,
Ptotal = Poxygen + P water
Substituting for Poxygen, we have;
Poxygen = Ptotal - P water vapor
P oxygen = 95 .00 kPa - 2.33 kPa
P oxygen = 92.67 kPa.
The partial pressure of oxygen gas in the container is hence, 92.67kPa.
