What is the molecular shape and bond angle at the indicated carbon?

Desalination is the process of converting sea water into drinking water. Older processes used a desalination method to desalinat

Kay [80]

Answer:

From the diagram, the water is being boiled. This process vaporises the water in the vessel leaving salt crystals behind.

Since the water is needed in liquid form, the cold water at the top of the set-up

condenses the vapor so it can be used.

3 0

3 years ago

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Which of the following compounds would be named with a name that ends in -ene?

krek1111 [17]

Answer:

The answer is option D.

CH3-CH2-CH2-CH=CH2

it's name is <u> Pentene</u> and it's an alkene

Hope this helps you

7 0

3 years ago

A chemical reaction is done in the setup shown , resulting in a change of mass. What will happen if the same reaction is done in

irina1246 [14]

<h2>Answer:</h2>

The mass of the system will remain the same if there is no conversion of mass to energy in the reaction.

<h3>Explanation:</h3>

If the system is closed, then according to the law of mass conservation the mass of the reaction system will remain the same.
<u><em>Law of conservation of the mass: In simple words, it is described as the mass of a closed system can never be changed, it may transfer from one form to another or change into energy.</em></u>
But if the reaction involves energy transfer like heat or light production, in this case, the mass can be changed.

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3 years ago

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1. In an equilibrium experiment, acetic acid (which is a weak acid) is mixed with sodium acetate (a soluble salt), with methyl o

koban [17]

Explanation:

It is known that acetic acid is a weak acid. It's equilibrium of dissociation will be represented as follows.

$CH_{3}COOH(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COO^{-}(aq) + H_{3}O^{+}(aq)$

On the other hand, sodium acetate ( $CH_{3}COONa$ ) is a salt of weak acid, that is, $CH_{3}COOH$ and strong base, that is, NaOH. Therefore, aqueous solution of sodium acetate will be basic in nature.

Since, acetic acid is a weak acid but still it is an acid. So, when methyl orange is added in a solution of acetic acid then it given a reddish-orange color because of its acidity.

When sodium acetate is mixed into this solution then it will dissociate as follows.

$CH_{3}COO^{-}Na^{+}(aq) \rightleftharpoons CH_{3}COO^{-}(aq) + Na^{+}(aq)$

As both solutions are liberating acetate ion upon dissociation. Hence, it is the common ion.

So, when more acetate ions will increase from dissociation of sodium acetate the according to Le Chatelier's principle the equilibrium will shift on left side.

As a result, there will be decrease in the concentration of hydronium ions. As a result, there will be increase in the pH of the system.

Hence, color of methyl orange will change from reddish orange to yellow. This shift in equilibrium is due to the common ion which is $CH_{3}COO^{-}$ ion.

4 0

3 years ago

The addition of NaOH to water would result in which of the following?

EleoNora [17]

Answer:

A decrease in [H3O+] and an increase in pH (option a)

Explanation:

Equilibrium of water is shown in this equation

2H₂O ⇄ H₃O⁺ + OH⁻

When you add NaOH, you are modifying [OH⁻]

NaOH → Na⁺ + OH⁻

In equilibrium of water, the [OH⁻] increases

2H₂O ⇄ ↓ H₃O⁺ + OH⁻ ↑

As the [OH⁻] increases, by Le Chatellier, the equilibrium tends to decrease [H₃O⁺].

If the [OH⁻] is higher, pH is also high so the solution of water and sodium hydroxide would be totally basic.

3 0

3 years ago