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3 years ago

2. Water should not be used to put electrical fires?

Chemistry

2 answers:

Ivan3 years ago

7 0

Answer:

The best way to put out an electrical fire is with a fire extinguisher. ... You should never throw water on an electrical fire because water conducts electricity and you could be electrocuted. 2. If you don't have a fire extinguisher, you can use baking soda to extinguish an electrical fire.

Explanation:

Can I get a brainliests please ☺️

Digiron [165]3 years ago

7 0

Answer:

You should never throw water on an electrical fire because water conducts electricity and you could be electrocuted.

Please mark 4 brainliests

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compound consists of carbon, hydrogen and fluorine. In one experiment, combustion of 2.50 g of the compound produced 3.926 g of

arlik [135]

Answer: The empirical and molecular formula of the compound is $CH_2F$ and $C_{14}H_{28}F_{14}$ respectively

Explanation:

We are given:

Mass of $CO_2=3.926g$

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 3.926 g of carbon dioxide, $\frac{12}{44}\times 3.926=1.071g$ of carbon will be contained.

To calculate the percentage composition of element in sample, we use the equation:

$\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100$ ......(1)

For Carbon:

Mass of carbon = 1.071 g

Mass of sample = 2.50 g

Putting values in equation 1, we get:

$\%\text{ composition of carbon}=\frac{1.071g}{2.50g}\times 100=42.84\%$

For Fluorine:

Mass of fluorine = 2.54 g

Mass of sample = 5.00 g

Putting values in equation 1, we get:

$\%\text{ composition of fluorine}=\frac{2.54g}{5.00g}\times 100=50.8\%$

Percent composition of hydrogen = [100 - 42.84 - 50.8] % = 6.36 %

We are given:

Percentage of C = 42.84 %

Percentage of F = 50.8 %

Percentage of H = 6.36 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 42.84 g

Mass of F = 50.8 g

Mass of H = 6.36 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.84g}{12g/mole}=3.57moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{6.36g}{1g/mole}=6.36moles$

Moles of Fluorine = $\frac{\text{Given mass of Fluorine}}{\text{Molar mass of Fluorine}}=\frac{50.8g}{19g/mole}=2.67moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.67 moles.

For Carbon = $\frac{0.072}{2.67}=1.34\approx 1$

For Hydrogen = $\frac{6.36}{2.67}=2.38\approx 2$

For Fluorine = $\frac{2.67}{2.67}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : F = 1 : 2 : 1

The empirical formula for the given compound is $CH_2F$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 448.4 g/mol

Mass of empirical formula = $12+(2\times 1)+19]=33g/mol$

Putting values in above equation, we get:

$n=\frac{448.4g/mol}{33g/mol}=13.6\approx 14$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(14\times 1)}H_{(14\times 2)}F_{(14\times 1)}=C_{14}H_{28}F_{14}$

Hence, the empirical and molecular formula of the compound is $CH_2F$ and $C_{14}H_{28}F_{14}$ respectively

3 0

3 years ago

Sodium-24 has a half life how much sodium-24 will remain in an 18 g sample after 75 hours

frutty [35]

Answer:

$\boxed{\text{0.56 g}}$

Explanation:

The half-life of Na-24 (15 h) is the time it takes for half of it to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

We can construct a table as follows:

No. of Fraction Mass

half-lives t/da Remaining Remaining/g

0 0 1 18

1 15 ½ 9.0

2 30 ¼ 4.5

3 45 ⅛ 2.2

4 60 ⅟₁₆ 1.1

5 75 ⅟₃₂ 0.56

6 90 ⅟₆₄ 0.28

We see that $\boxed{\textbf{0.56 g}}$ remain after five half-lives (75 h).

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3 years ago

How do catalysts increase the rate of a chemical reaction?

Nataly [62]

Answer:

They increase the concentration of the reactants

Explanation:

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4 years ago

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Debbie was doing a science lab, and she was instructed to decide whether a piece of plastic would float or sink without actually

Mandarinka [93]

Find the density of the plastic. if the density is less than that of water, it's going to float. If it's more than the density of water, then it's going to sink.

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3 years ago

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What is the correct name for the compound H2O

Deffense [45]

Answer:

The common name for the compound H2O is water.

Explanation:

The systemic name of H2O is Dihydrogen monoxide.

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3 years ago

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