Answer: (-31.09 mi, -20.97 mi)
Step-by-step explanation:
If the noon is our initial time, then we have that 2:30 pm is t = 2.5 hours.
Now, the position (x, y) of the ship can be writen as:
(velocity*time*cos(angle), velocity*time*sin(angle))
or:
(15mph*t¨*cos(214°), 15mph*t*sin(214°))
then the position at t = 2.5 hours is:
(15mph*2.5h*cos(214°), 15mph*2.5h*sin(214°))
(-31.09 mi, -20.97 mi)
Answer:
(-∞, ∞).
Step-by-step explanation:
This function can have any real value.
Range = (-∞, ∞).
Each equation form a straight slanting line. For the first equation, it is slanting towards the right which denotes that it has a positive slope. For the the second equation, its plot is slanting towards the left denoting that its slope is negative. Common to both equation is the point (-1.25, 2.75). At this point, the two lines intersect.
Learn this :
VUX -- vertical line, undefined slope, represented by x = a number.
HOY -- horizontal line, 0 slope, represented by y = a number
so the line with the undefined slope is going to be x = 2
