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Stels [109]
3 years ago
9

Which of these groups of elements show the least electronegativity?

Chemistry
2 answers:
alexandr1967 [171]3 years ago
6 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Electronegativity is defined as the property of as element to attract the shared pair of electron towards itself. The value of electronegativity is high for non-metals because they can easily gain electrons as compared to the metals.

This value decreases as we move down the group and increases as we move across a period.

Halogens are the elements which belong to Group 17. They easily gain electrons in order to attain stability. Thus, these elements have high electronegativity values.

Alkali metals are the elements which belong to Group 1. They easily loose electrons in order to attain stability and thus have low electronegativity.

Transition elements are the elements which belong from Group 3 to Group 12. They easily loose electrons in order to attain stability and thus have low electronegativity.

Alkaline earth metals are the elements which belong to Group 2. They easily loose electrons in order to attain stability and thus have low electronegativity.

From the above information, the elements which belong o Group 1 have the lowest electronegativity values.

Hence, the correct answer is Option B.

Nady [450]3 years ago
5 0

the answer is c if you are using plato

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The given question is incomplete. the complete question is:

The world burns the fossil fuel equivalent of approximately 9.50\times 10^{12} kg of petroleum per year. Assume that all of this petroleum is in the form of octane. Calculate how much CO2 in kilograms is produced by world fossil fuel combustion per year.( Hint: Begin by writing a balanced equation for the combustion of octane.)

Answer: 29\times 10^{12}kg

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2_C8H_{18}+17O_2\rightarrow 16CO_2+18H_2O

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of octane}=\frac{9.50\times 10^{12}\times 10^3g}{114g/mol}=0.083\times 10^{15}moles

According to stoichiometry :

As 2 moles of octane give = 16 moles of CO_2

Thus 0.083\times 10^{15}moles of octane give =\frac{16}{2}\times 0.083\times 10^{15}=0.664\times 10^{15}moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=0.664\times 10^{15}moles\times 44g/mol=29.2\times 10^{15}g=29.2\times 10^{12}kg

Thus 29\times 10^{12}kg of CO_2 is produced by world fossil fuel combustion per year.

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