Hey there!:
HA <=> H⁺ + A⁻
pH = -log[H+] = 6
[ H⁺ ] = 10^-pH
[ H⁺] = 10 ^ -6
[ H⁺ ] = 0.000001 M
Percent dissociation:
[ H⁺ ] / [ HA]o * 100
[ 0.000001 / 0.10 ] * 100
0.00001 * 100 => 0.0010%
Answer D
Hope that helps!
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