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telo118 [61]
3 years ago
13

What is the mass of a gold bar that is 7.379*10^-4 m^3 in volume?

Chemistry
1 answer:
NISA [10]3 years ago
8 0
Mass to volume
M^3 --> cm^3
Cm^3 --> mL
Centi = 10*-2
7.379*10-4 / 1*10-2 = .07379

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(A) C6H5NH2 -         4 x 10^-10                      9.349

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