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bezimeni [28]
2 years ago
13

I have no clue how I’m supposed to do this…

Mathematics
2 answers:
ioda2 years ago
5 0
Refer to the photo. Use Pythagorean theorem of a^2 + b^2 = c^2

Irina-Kira [14]2 years ago
3 0

Answer:

Step-by-step explanation:

We will need to rewrite the Pythagorean Theorem

A^2 + B^2 = C^2

Substitute. tIn this case:

18^2 + x^2 = 82^2

Subtract 18^2

x^2 = 82^2 - 18^2

In order to get x alone, take the root:

x = sqrt(82^2 - 18^2)

And solve:

x = 80

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When does expanding and simplifying a(b+c) result in a positive value for ac
TiliK225 [7]

Answer:


Step-by-step explanation:

(ab + bc)(ab + bc)

Simplifying

(ab + bc)(ab + bc)

Multiply (ab + bc) * (ab + bc)

(ab(ab + bc) + bc(ab + bc))

((ab * ab + bc * ab) + bc(ab + bc))

Reorder the terms:

((ab2c + a2b2) + bc(ab + bc))

((ab2c + a2b2) + bc(ab + bc))

(ab2c + a2b2 + (ab * bc + bc * bc))

(ab2c + a2b2 + (ab2c + b2c2))

Reorder the terms:

(ab2c + ab2c + a2b2 + b2c2)

Combine like terms: ab2c + ab2c = 2ab2c

(2ab2c + a2b2 + b2c2)

7 0
3 years ago
Prove the following identity true. Show work.
yulyashka [42]

Answer:

The  Pythagorean identity states that

\sin^2 t + \cos^2 t = 1

Using that we can rewrite the left denominator as:

1 - \sin^2 t

Which can be factored as

(1 - \sin t)(1+ \sin t)

The numerator we can expand as:

(1 - \sin t)(1 - \sin t)

On the right hand side, let's multply numerator and denominator with (1 - sin t):

The total formula then becomes:

\dfrac{(1-\sin t)(1-\sin t)}{(1 - \sin t)(1 + \sin t)} = \dfrac{(1-\sin t)(1 - \sin t)}{(1+\sin t)(1 - \sin t)}

There you go... left and right are equal.

3 0
3 years ago
Read 2 more answers
PLEASE HELP BRAINLY ANSWER
Tema [17]
I’m Not 100% Sure, But I Would Think 13.1% Is The Answer.
4 0
3 years ago
Read 2 more answers
The graph shows a function. Is the function linker or non linear?
zloy xaker [14]

Answer:

It is linear since it is a straight line.

8 0
2 years ago
Ppppppppeeeelelelelele help
kirill115 [55]
11/3*6/11=66/33=2
6 24/20-2 15/20=2 9/20
5 0
3 years ago
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