We want to find an equation for the given solutions and the multiplicity of each solution.
The equation is:
First, assume that we have a given equation and we know that we have solutions {x₁, x₂, ..., xₙ}, each one with multiplicity {m₁, ..., mₙ}.
The equation, of a polynomial that meets these requirements, is given by:
Where A is the leading coefficient and can be any real number.
Now that we know that, here we have the solutions:
- x = 2 with multiplicity 2
- x = -1 with multiplicity 2
We don't have information about the leading coefficient, so we assume it is equal to 1.
Then the equation is:
If you want to learn more, you can read:
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Answer:
ajjvtjeiqwchiedgvgfeggyryftyyyug ytugttbghg
Answer:
B
Step-by-step explanation:
Answer:
21nk
Step-by-step explanation:
We need to get the denominators to be the sameso what can you do to 5d and d^2 to be the same? If you multiply 5d by d you get 5d^2 and if you multiply d^2 by 5 you get 5d^2. And whatever you have to do to the denominator you do to the numerator.
Once you have the same denominator you can just add or subtract the numerators as needed. You don't need to do this for multiplication or division
Multiplying is super easy, just multiply the denominators and the numerators.
Let me know if you don't get how things canceled out.
Division is almost as simple as multiplication. The second fraction gets flipped and you multiply them.
Again, let me know if you don't understand how things cancel out or got multiplied or something else.