Answer:
The numerical length of JL is 6 units
Step-by-step explanation:
Here, we want to determine the numerical length of JL
Mathematically;
JL = JK + KL
2x + 8 = 5x + 7 + 4
2x + 8 = 5x + 11
5x -2x = 8-11
3x = -3
x = -1
But JL = 2x + 8
JL = 2(-1) + 8 = -2 + 8 = 6
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:
B. h=2A/(b1+b2) . . . . parentheses are needed
Step-by-step explanation:
Multiply the equation by the inverse of the coefficient of h. That coefficient is (b1 +b2)/2, so its inverse is 2/(b1 +b2). Parentheses are needed.
... 2A/(b1 +b2) = h
_____
<em>Comment on the answer choices</em>
As written, <em>none of them are correct</em>. The denominator can only be written without parentheses if the division bar is horizontal, and so serves also as a grouping symbol.
30 x 0.33 = 9.90 And that's the answer
