Why do we use variables, and what is the significance of using them in expressions and equations?

a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou

Fed [463]

Answer:

$\displaystyle P(A)=\frac{6}{11}$

Step-by-step explanation:

Probabilities

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

$\Omega=\{WW,WN,NW,NN\}$

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

$A=\{WN,NW\}$

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

$\displaystyle \frac{5}{11}$

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

$\displaystyle \frac{6}{10}$

Thus the option WN has the probability

$\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}$

Now for the second option NW. The initial probability to pick a non-white counter is

$\displaystyle \frac{6}{11}$

The probability to pick a white counter is

$\displaystyle \frac{5}{10}$

Thus the option NW has the probability

$\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}$

The total probability of event A is the sum of both

$\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}$

$\boxed{\displaystyle P(A)=\frac{6}{11}}$

7 0

3 years ago

Please help!!!!!!!!!!!!!!!

Andreas93 [3]

Answer:

a) 12/91

b) about 67 times; (66 2/3)

Step-by-step explanation:

a) total of frequencies is 90 and frequency for a 3 is 11

however, the question said if the dice is rolled once more, then that raises the 11 to 12 and the frequency total from 90 to 91

let 'x' = # of sixes rolled out of 500 times

b) 12/90 = x/500

cross-multiply:

90x = 6000

x = 66 2/3

7 0

3 years ago

Given only the information in the diagram, determine if m is parallel to n. If so, name the postulate or theorem used to support

Advocard [28]

Answer:

From my research on the internet, the image attached supports this problem. The two lines are parallel, as supported by the converse of corresponding angles postulate. It states that: If a transversal intersects two lines and the corresponding angles are congruent, then the lines are parallel.

8 0

3 years ago

What is 12/39 in simplest form

Genrish500 [490]

If you would like to know what is 12/39 in simplest form, you can calculate this using the following step:

12/39 simplifies to 4/13 (the common factor of 12 and 39 is 3, so you can divide both numbers by 3).

The result is 4/13.

8 0

3 years ago

Read 2 more answers

Give letter answer if you give equations rewritten I will give extra points :)

padilas [110]

Answer:

(a), (d)

Step-by-step explanation:

7 0

2 years ago