40-15=g so they scored 25 this year and 25+15=40
<span>y = 300 - 5x
Standard form:
ax + by = c
</span>y = 300 - 5x
<span>5x + y = 300
Then to find the y-intercept, insert a 0 into the 'x'.
5(0) + y = 300
y = 300
The y-intercept is 300.
To find the x-intercept, insert a 0 into the 'y'.
5x + (0) = 300
5x = 300
x = 60
The x-intercept is 60.</span>
Answer:
3x² + x - 3
Step-by-step explanation:
The way I like to do it is to get rid of the x's and just use the numbers in the case of synthetic division
Pretend the square root of the division symbol
-4 √ 3 12 1 -12
Quick note: We're dividing by -4 because we're dividing by x + 4
First bring down the 3
-4 √ 3 13 1 -12
3
Multiply it by 4 then bring add it to the next number
-4 √ 3 13 1 -12
-12
3 1
Add that number to the next one
-4 √ 3 13 1 -12
-12 -4
3 1 -3
Finally repeat the step for the last number
-4 √ 3 13 1 -12
3 -12 -4 +12
3 1 -3 0
Now take those bottom numbers and add back the x's but with one less power, so the starting x³ would now become x², x² would become x, and so on
3x² + 1x - 3
Answer:
![\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
This tells us that:
![A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D)
![b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=b%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
So we are saying we have scalars, c and d, such that:
![c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=c%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C5%5C%5C%203%5Cend%7Barray%7D%5Cright%5D%2Bd%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%5C%5C-8%5C%5C-9%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
.
So we want to find a way to express this as:
Ax=b where x is the scalar vector, ![\left[\begin{array}{ccc}c\\d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D)
.
So we can write this as:
<span>Math Term Definition. Algebraic Expression. An algebraic expression
is a mathematical phrase that can contain ordinary numbers, variables
(like x or y) and operators (like add,subtract,multiply, and divide).
Here are some algebraic expressions: a + 1.</span>
