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Nina [5.8K]
2 years ago
10

MARKING BRAILIEST!!!! Select the statement that describes this expression: 13 + fraction 1 over 2 x (6 ÷ 2 + 6)

Mathematics
2 answers:
Sindrei [870]2 years ago
7 0

Answer:

a

Step-by-step explanation:

Sauron [17]2 years ago
3 0

Answer: D

You get the same answer from doing both!

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How would I do part A. I showed my work but I'm slightly off
ahrayia [7]

\bf \stackrel{\textit{perimeter of the rectangle}}{P_{rect}=2x+y}~\hfill \stackrel{\textit{area of the rectangle}}{A_{rect}=xy}
\\\\\\
\stackrel{\textit{perimeter of the semi-circle, with }r=\frac{y}{2}}{P_{semic}=\cfrac{\pi y}{2}}~\hfill \stackrel{\textit{area of the semi-circle with }r=\frac{y}{2}}{A_{semic}=\cfrac{\pi y^2}{8}}
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf \stackrel{\textit{perimeter of the enclosure}}{60=2x+y+\cfrac{\pi y}{2}}\implies \stackrel{\textit{multiplying by 2}}{120=4x+2y+\pi y}
\\\\\\
120-2y-\pi y=4x\implies \cfrac{120-2y-\pi y}{4}=x
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf \stackrel{\textit{area of the enclosure}}{A=xy+\cfrac{\pi y^2}{8}}\implies A=\left( \cfrac{120-2y-\pi y}{4} \right)y+\cfrac{\pi y^2}{8}
\\\\\\
A=\cfrac{120y-2y^2-\pi y^2}{4}+\cfrac{\pi y^2}{8}\implies A=\cfrac{240y-4y^2-2\pi y^2+\pi y^2}{8}
\\\\\\
A=\cfrac{240y-4y^2-\pi y^2}{8}\implies A=\cfrac{240y}{8}-\cfrac{4y^2}{8}-\cfrac{\pi y^2}{8}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill A=30y-\cfrac{1}{2}y^2-\cfrac{1}{8}\pi y^2~\hfill

5 0
3 years ago
A function h(x) is defined by the formula h(x)=x^3-3. What is the value of g(h(2))?
Sauron [17]

Answer:

g(h(2))= 5

Step-by-step explanation:

h(x)=x^3-3

g(2^3-3)

the 2 replaces the x

simplify

g(5)

7 0
3 years ago
4c-2d÷c elvauate for c= 2 and d=5. Enter your numerical number
jok3333 [9.3K]
You just need to substitute 4(2)-2(5)/2
8-10/2
8-5
=3
4 0
2 years ago
Read 2 more answers
Find a point on the curve x^3+y^3=11xy other than the origin at which the tangent line is horizontal.
attashe74 [19]

Compute the derivative dy/dx using the power, product, and chain rules. Given

x³ + y³ = 11xy

differentiate both sides with respect to x to get

3x² + 3y² dy/dx = 11y + 11x dy/dx

Solve for dy/dx :

(3y² - 11x) dy/dx = 11y - 3x²

dy/dx = (11y - 3x²)/(3y² - 11x)

The tangent line to the curve is horizontal when the slope dy/dx = 0; this happens when

11y - 3x² = 0

or

y = 3/11 x²

(provided that 3y² - 11x ≠ 0)

Substitute y into into the original equation:

x³ + (3/11 x²)³ = 11x (3/11 x²)

x³ + (3/11)³ x⁶ = 3x³

(3/11)³ x⁶ - 2x³ = 0

x³ ((3/11)³ x³ - 2) = 0

One (actually three) of the solutions is x = 0, which corresponds to the origin (0,0). This leaves us with

(3/11)³ x³ - 2 = 0

(3/11 x)³ - 2 = 0

(3/11 x)³ = 2

3/11 x = ³√2

x = (11•³√2)/3

Solving for y gives

y = 3/11 x²

y = 3/11 ((11•³√2)/3)²

y = (11•³√4)/3

So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).

3 0
2 years ago
A species of bacteria is 10 micrometers long. A virus is 10,000 times smaller than bacteria. a. Using the table above, find the
stich3 [128]

Answer:

10^{-4} times 10 micrometers (or 10^{-5}) is 10^{-9}

8 0
3 years ago
Read 2 more answers
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