Pls help i know x= 8

What expression is equivalent to -15x + 39? *

Nookie1986 [14]

Answer:

-15x + 39 = -3(5x - 13)

Step-by-step explanation:

a. -3(5x - 13) = -15x + 39

b. -3(5x + 13) = -15x - 39

c. 3(5x - 13) = 15x - 39

d. 3(5x + 13) = 15x + 39

7 0

3 years ago

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

1,3,2,6,3,9,4,12... what will be the eleventh number in the pattern?

katrin [286]

Answer:

11th number is 6

Step-by-step explanation:

7 0

1 year ago

Read 2 more answers

$1800 at 6.5% for 30 months

nasty-shy [4]

1800×6.5%×30=b
b-1800=a

a) $1,710

b) $3,510

8 0

3 years ago

How many solutions does the system have? 2x+3y=-6 3x-4y=-12. A) exactly one solution b) no solution c) infinity many solutions

katovenus [111]

Answer:

a.

Step-by-step explanation:

by elimanation,cimparison or substitution you wull get the value of x=-60/17 and y=6/17

8 0

3 years ago