The empirical formula of a compound is determined to be CH2O, and its molecular mass is found to be 90.087 g/mol. Determine the molecular formula of the compound, showing your solution.
Answer: This is actually quite simple, first we have to calculate the molar mass of empirical unit. Therefore we have 12+2*1+16 = 30. Then we solve 90/30 = 3. Finally we end up with 3*(CH2O) --> C3H6O3.
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I believe that it is 187.56 g/mol
Answer:
1. The ground state describes the lowest possible energy that an atom can have. An electron is normally in its ground state, the lowest energy state available.
2. In a metal, atoms readily lose electrons to form positive ions (cations). These ions are surrounded by delocalized electrons, which are responsible for conductivity. The solid produced is held together by electrostatic interactions between the ions and the electron cloud. These interactions are called metallic bonds. The metallic bonding model explains the physical properties of metals. Metals conduct electricity and heat very well because of their free-flowing electrons. As electrons enter one end of a piece of metal, an equal number of electrons flow outward from the other end.
3. Physical properties are affected by the strength of intermolecular forces. Melting, boiling, and freezing points increase as intermolecular forces increase. Vapor pressure decreases as intermolecular forces increase. The physical state and properties of a particular compound depend in large part on the type of chemical bonding it displays. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound.
Explanation:
This is from 38 minutes ago. Sorry for late reply. I really hope this helps. :)
Answer:
(c) temperature
Explanation:
In a closed system, as the temperature increases, the molecules in the liquid are exited and converts into gas. The more the gas transformed, the more the gas(vapor) pressure. The less the gas transformed, the less the vapor pressure.
Therefore, temperature is a major factor in vapor pressure.
