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2 years ago

Which ionic compound would you predict to have a higher boiling point: NaBr or

Chemistry

1 answer:

nasty-shy [4]2 years ago

8 0

Answer:

The boiling point of NaBr is higher than that of Na2S

Explanation:

Bromine has higher electronegativity as compared to the sulphur. The ionic strength of the bond formed with Sodium is higher in the NaBr compound. The higher the ionic bond strength the higher will be the boiling point

Also the size of bromine is large as compared to that of sulphur. Large molecules consists of more electron and hence they create der Waals attractive forces due to which the boiling point of compound increases.

Hence, the boiling point of NaBr is higher than that of Na2S

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the reaction between nitrogen and hydrogen to produce ammonia is described by the following equilibrium reaction. 3h2 n2↽−−⇀2nh3

eimsori [14]

N₂, H₂, NH₃ are present in the reaction mixture when equilibrium has been obtained.

Balanced chemical reaction: 3H₂ + N₂ ⇄ 2NH₃

Hydrogen (H₂ ) and nitrogen (N₂) are reactants.

Ammonia (NH₃) is product of the reaction.

Reaction goes in both direction, both reactants and product are present.

The amount of substance of reactants and products of reaction do not change when chemical reaction is in chemical equilibrium.

In a chemical reaction, chemical equilibrium is the state in which both reactants and products are present in concentrations which not change with time.

Speed of direct and irreversible chemical reaction are equal.

More about equilibrium: brainly.com/question/25651917

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1 year ago

Baker’s Yeast is usually added to dough in baking products. It contains enzymes (catalysts) that are necessary for the rising do

STatiana [176]

Answer:

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2 years ago

How many moles of KClO3 are produced from 25 moles of KCL

e-lub [12.9K]

Answer: 25

Explanation:

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2 years ago

A mixture contains only nacl and al2(so4)3. a 1.45 g sample of the mixture is dissolved in water, and an excess of naoh is added

Aleks [24]

When mixture of NaCl and Al₂(SO₄)₃ is allowed to react with excess NaOH, only Al₂(SO₄)₃ reacts with it and NaCl does not react with NaOH due to presence of common ion (Na⁺). On reaction gelatinous precipitate of aluminium hydroxide [Al(OH)₃] is produced. The balanced chemical reaction is represented as-

Al₂(SO₄)₃ + 6NaOH → 2Al(OH)₃ + 3Na₂SO₄

On this reaction, 0.495 g = 0.495/78 moles =6.346 X 10⁻³ moles of Al(OH)₃.

As per balanced reaction, two moles of Al(OH)₃ is produced from one mole Al₂(SO₄)₃. So, 6.346 X 10⁻³ moles of Al(OH)₃ is produced from (6.346 X 10⁻³)/2 moles=3.173 X 10⁻³ moles of Al₂(SO₄)₃= 3.173 X 10⁻³ X 342 g of Al₂(SO₄)₃=1.085 g of Al₂(SO₄)₃.

So, mass percentage of Al₂(SO₄)₃ is= (amount of Al₂(SO₄)₃/total amount of mixture)X100 = $\frac{1.085 X 100}{1.45}$ =74.8 %.

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3 years ago

Help me answer this question for points!

labwork [276]

Answer:

I am pretty sure Danny Duncan told me 69

Explanation:

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3 years ago