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Mrac [35]
2 years ago
10

What is 5 ounces in milliliters?

Chemistry
1 answer:
SIZIF [17.4K]2 years ago
6 0
1 ounces ----------- 29.5735 mL
5 ounces ----------- ??

5 x 29.5735 / 1 => 147.868 mL

hope this helps!
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If 9.85 grams of copper metal react with 31.0 grams of silver nitrate, how many grams of copper nitrate can be formed and how ma
goldfiish [28.3K]
The balanced chemical reaction:

<span>Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
</span>
We are given the amount of the reactants to be used for the reaction. These values will be the starting point of our calculations.

9.85 g Cu ( 1 mol Cu / 63.55 g Cu ) = 0.15 mol Cu
31.0 g AgNO3 ( 1 mol AgNO3 / 169.87 g AgNO3 ) = 0.18 mol AgNO3

The limiting reactant is AgNO3.

0.18 mol AgNO3 ( 1 mol Cu(NO3)2 / 2 mol AgNO3 ) (187.56 g / 1 mol) =16.88 g Cu(NO3)2

0.15 mol Cu - 0.18 mol AgNO3 ( 1 mol Cu / 2 mol AgNo3) = 0.06 mol Cu excess

<span>0.06 mol Cu ( 63.55 g Cu / 1 mol Cu ) = 3.81 g Cu excess</span>
3 0
3 years ago
Read 2 more answers
Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C.
Ad libitum [116K]

Explanation:

The given data is as follows.

    Concentration = 0.1 mol/dm^{3}

                             = 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

                             = 6.022 \times 10^{25} ions/m^{3}

               T = 30^{o}C = (30 + 273) K = 303 K

Formula for electric double layer thickness (\lambda_{D}) is as follows.

            \lambda_{D} = \frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}

where, n^{o} = concentration = 6.022 \times 10^{25} ions/m^{3}

Hence, putting the given values into the above equation as follows.

                 \lambda_{D} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}                    

                          = \sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}  

                         = 9.669 \times 10^{-10} m

or,                     = 9.7 A^{o}

                          = 1 nm (approx)

Also, it is known that \lambda_{D} = \sqrt \frac{1}{n^{o}}

Hence, we can conclude that addition of 0.1 mol/dm^{3} of KCl in 0.1 mol/dm^{3} of NaBr "\lambda_{D}" will decrease but not significantly.

7 0
3 years ago
What is 5 ounces in milliliters?
SIZIF [17.4K]
1 ounces ----------- 29.5735 mL
5 ounces ----------- ??

5 x 29.5735 / 1 => 147.868 mL

hope this helps!
6 0
2 years ago
The Gateway Arch in St. Louis, MO is approximately 630 ft tall. How many U.S. half dollars would be in a stack of the same heigh
Paraphin [41]

Answer:

The number of half dollars in the stack of the height of the Gateway Arch in St. Louis is 89,313 half dollars

Explanation:

The given height of the Gateway Arch in St. Louis = 630 ft

The thickness of each half dollar = 2.15 mm

By conversion of factors, we have;

1 feet = 304.8 mm

Therefore;

630 ft. = 304.8 × 630 mm = 192,024 mm

The number of half dollars that will stack up to 630 ft or 192,024 mm, is therefore, given as follows;

The number, n, of half dollars in the stack of the height of the Gateway Arch in St. Louis = The height of the Gateway Arch in St. Louis/(The thickness of each half dollar)

n = 630 ft/(2.15 mm/(half dollar)) = 192,024 mm/(2.15 mm/(half dollar)) = 89,313.49 ≈ 89,313 half dollars

The number of half dollars in the stack of the height of the Gateway Arch in St. Louis = 89,313 half dollars.

6 0
2 years ago
What does MA 2 means?​
erica [24]

Answer:

Master-at-Arms Petty Officer 2nd Class. MA2. Machine Accountant Second Class (Naval Rating) Copyright 1988-2018 AcronymFinder.com, All rights reserved.

Explanation:

5 0
3 years ago
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