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Alexus [3.1K]
3 years ago
9

Transfer 2-3 drops of each solution onto the indicator paper. Be sure to

Chemistry
1 answer:
alexira [117]3 years ago
4 0

Answer:

0.1 M HCl pH: 1-2

0.001 M HCl pH: 3-4

0.00001 M HCl pH: 5-6

Distilled Water pH: 7

0.00001 M NaOH pH: 8-9

0.001 M NaOH pH: 10-11

0.1 M NaOH pH: 12-13

Explanation:

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What is the molecular geometry of PBr3? A. trigonal pyramidal B. trigonal planar C. linear D....
lubasha [3.4K]
The correct answer is:

TRIGONAL PYRAMIDAL
4 0
3 years ago
The watt is the standard unit of measurement for? ​
Crazy boy [7]

Answer:

electrical power. nnnnnnn

3 0
3 years ago
All of the following contribute to the large, negative, free-energy change upon hydrolysis of "high-energy" compounds except: a.
klasskru [66]

Answer:

C) low activation energy of forward reaction

Explanation:

Activation energy for the forward reaction is the quantity of free energy which is needed for a reaction to move from the reactant phase of energy level to the transition state of energy level. The higher the rate of energy level, the slower the chemical reaction.

Activation energy is a barrier that must be overcome for a reaction to take place.

8 0
3 years ago
How many moles of Ca(OH)2 are needed to make 2.5 moles of CaCl2?
barxatty [35]

Explanation:

CaCl2 ⇄ Ca-²+2Cl-¹

1mole⇄1mole+2moles

So from above ..

1mole CaCl2 produce 1mole Ca-² & 2 moles of Cl-².

For 2.5 moles we multiply the above chemical eq. With 2.5

2.5CaCl2⇄2.5Ca-²+5Cl-¹

So from 2.5 moles of CaCl2 we get 2.5 mole calcium ion and 5 moles chloride ion…

5 0
2 years ago
Consider the reaction.
sveta [45]

The percent yield of reaction = 65.27%

<h3>Further explanation</h3>

Reaction

2Pb(s)+O₂(g)⟶2PbO(s)

mass of Lead(Pb) = 451.4 g

mol of Pb (MW=207 g/mol) :

\tt \dfrac{451.4}{207}=2.18

mol of lead(II) oxide (PbO) based on mol Pb as a limiting reactant(Oxygen as an excess reactant) :

\tt \dfrac{2}{2}\times 2.18=2.18

mass of PbO(MW=223 g/mol)⇒theoretical :

\tt 2.18\times 223=486.14~g

The percent yield :

theoretical = 486.14 g

actual = 317.3 g

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{317.3}{486.14}\times 100\%=65.27\%

5 0
2 years ago
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