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valentina_108 [34]
3 years ago
12

A box contains 9 plain pencils and 1 pen. A second box contains 5 color pencils and 5 crayons. One Iter from each box is chosen

at random. What is the
probability that a plain pencil from the first box and a color pencil from the second box are selected?
Write your answer as a fraction in simplest form.
0
DO
X
х
?
Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

9/2 or if that doesn't work try 4 1/2

Step-by-step explanation:

The probably of getting a plain pencil from the first box is 9/10. The probability of getting a color pencil from the second box is 5/10. If you multiply those you get 9/2 or 4 1/2.

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Answer:

\begin{equation}&#10;\sqrt{3}-1,2 \sqrt{10} \div 5, \sqrt{14}, 3 \sqrt{2}, \sqrt{19}+1,6&#10;\end{equation}

Explanation:

Given the irrational numbers:

$3 \sqrt{2}, \sqrt{3}-1, \sqrt{19}+1,6$, $2 \sqrt{10} \div 5,\sqrt{14}$

In order to arrange the numbers from the least to the greatest, we convert each number into its decimal equivalent.

\begin{gathered} 3\sqrt{2}=3\times1.414\approx4.242 \\ \sqrt{3}-1\approx1.732-1=0.732 \\ \sqrt{19}+1\approx4.3589+1=5.3589 \\ 6=6 \\ 2\sqrt{10}\div5=2(3.1623)\div5=1.2649 \\ \sqrt{14}=3.7147 \end{gathered}

Finally, sort these numbers in ascending order..

\begin{gathered} \sqrt{3}-1\approx1.732-1=0.732 \\ 2\sqrt{10}\div5=2(3.1623)\div5=1.2649 \\ \sqrt{14}=3.7147 \\ 3\sqrt{2}=3\times1.414\approx4.242 \\ \sqrt{19}+1\approx4.3589+1=5.3589 \\ 6=6 \end{gathered}

The given numbers in ascending order is:

\begin{equation}&#10;\sqrt{3}-1,2 \sqrt{10} \div 5, \sqrt{14}, 3 \sqrt{2}, \sqrt{19}+1,6&#10;\end{equation}

Note: In your solution, you can make the conversion of each irrational begin on a new line.

8 0
1 year ago
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