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wariber [46]
2 years ago
13

What are the solutions of the equation 6x2 + x-1=0 ?

Mathematics
1 answer:
Aleksandr [31]2 years ago
6 0

Answer:

<u>Options B and D</u>

Step-by-step explanation:

6x² + x - 1 = 0

6x² + 3x - 2x - 1 = 0

3x(2x + 1) - 1(2x + 1) = 0

(3x - 1)(2x + 1)

x = 1/3 and -1/2

<u>Options B and D</u>

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Frank has devised a formula for his catering business that calculates the number of meatballs he needs to prepare.
timofeeve [1]
Just plug in the numbers into the equation.

m = 4a + 2c

a = adults
c = children
m = meatballs

The information given says there are 25 adults and 5 children. So now:

a = 25
and
c = 5
in the equation m = 4a + 2c


Now plug in the values. 
m = 4(25) + 2(5)
m = 100 + 10
m = 110

This means that 110 meatballs are required for 25 adults and 5 children. 
8 0
3 years ago
What is the total finance charge for a $4,250 loan at 13.25% interest compounded monthly for 24 months?
Rom4ik [11]
Since only the principal value, interest rate and interest period are given, we can deduce that "finance charge" only includes the interest to be paid at the end of the term. This can be obtained by subtracting the principal value from the future value which we will solve for.

The future value can be solved by using the following compound interest formula:

Let:
F = Future value
P = Principal value
r<span> = annual interest rate </span>
n<span> = number of times that interest is compounded per year</span>
t<span> = number of years</span>

F = P(1 + r/n)^nt

Substituting the given values:
F = 4250(1 + 0.1325/12)^(12*2)
F = 5531.54

Subtracting P from F:
Finance charge = 5531.54 - 4250 = 1281.54

Therefore the finance charge is $1,281.54
6 0
3 years ago
Because of their connection with secant​ lines, tangents, and instantaneous​ rates, limits of the form ModifyingBelow lim With h
Gre4nikov [31]

Answer:

\dfrac{1}{2\sqrt{x}}

Step-by-step explanation:

f(x) = \sqrt{x} = x^{\frac{1}{2}}

f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}

From the expansion

(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots

Setting x=\dfrac{h}{x} and n=\frac{1}{2},

(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots

=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots

Multiplying by x^{\frac{1}{2}},

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots

The limit of this as h\to 0 is

\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}} (since all the other terms involve h and vanish to 0.)

8 0
3 years ago
Can anyone say how is Brainly app I'm new here​
mars1129 [50]

Answer:

u can ask question and answer question when u answer q u get point and leve up

3 0
3 years ago
Read 2 more answers
12 yo<br> 5 yd<br> what is the length of the hypotenuse
Allushta [10]

I'm sure that the hypotenuse is 13 yards

Here's the formula used:

Length of Hypotenuse² = Length of side 1² + Length of side 2²

So here's how to solve this question:

12 squared + 5 squared = hypotenuse

(Then square the values)

144 + 25 = 169

Divide 169 by the square root to get the length of the hypotenuse: 13

Hope this helps!

7 0
3 years ago
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