Answer:
B) (35, 260)
Step-by-step explanation:
A veterinarian will prescribe an antibiotic to a dog based on its weight. The effective dosage of the antibiotic is given by d ≥ 1∕5w2, where d is dosage in milligrams and w is the dog's weight in pounds. Which of the following ordered pairs gives an effective dosage of antibiotics for a 35-pound dog?
A) (35, 240)
B) (35, 260)
C) (260, 35)
D) (240, 35)
Ordered pairs is composed of pairs, usually an x coordinate and a y coordinate. It refers to a location of a point on the coordinate. It matches numbers to functions or relations.
Given the relation between d is dosage in milligrams and w is the dog's weight in pounds as d ≥ 1∕5w²
For a 35 pound dog (i.e w = 35 pound). The dosage is given as:
d ≥ 1∕5(35)² ≥ 245 milligrams.
For an ordered pair (x, y), x is the independent variable (input) and y is the dependent variable (output).
The dog weight is the independent variable and the dosage is the dependent variable.
From the ordered pairs, the best option is (35, 260) because 260 ≥ 240
Answer:
good luck
Step-by-step explanation:
the mean is all of them added up then divided by how many numbers there are the median is where you put them in order putting the numbers in order then finding the middlel mode is the most of the same numbers and range is the biggest number
Answer:
14: 9
+
5
ℎ
15: −
1
6
+
9/
9
Step-by-step explanation:
14 : ℎ
⋅
5
+
(
9
)
5ℎ+
(9)
^^ Re-order terms so constants are on the left
5ℎ+
⋅
9 also 5
ℎ+9 then after this you would wanna re arange the terms so it would be 9
+
5
ℎ
Answer:
x ∈ {-5, -1}
Step-by-step explanation:
Here's the solution using the quadratic formula:
The real zeros are -5 and -1.
_____
There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.
Also, the constant in the quadratic is the product of the roots, For your roots, their product is -7/4, so even multiplying by 4 (the leading coefficient in the given quadratic), you don't get anything like 20.
I say it has to be b because it would make more sense
