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Archy [21]
3 years ago
7

Brainliest if correct

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

3/8 & 4/8

Step-by-step explanation:

1/2 - 1/8 = 4/8 - 1/8 = 3/8

x - 1/8 = 3/8

x = 4/8    

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Help me solve this please I’m struggling
mrs_skeptik [129]

9514 1404 393

Answer:

  • 9.5
  • maximum, 34.5, 5
  • 10.9

Step-by-step explanation:

I find it convenient to use a graphing calculator to graph the function.

The "start" is x=0, where the distance from the sprinkler head is 0 feet. The value of h(0) is 9.5, the height of the sprinkler head.

  • The irrigation system is positioned <u> 9.5 </u> feet above the ground.

The graph shows the vertex of the curve is (5, 34.5), meaning that a height of 34.5 feet is reached 5 feet horizontally from the sprinkler.

  • The spray reaches a <u> maximum </u> height of <u> 34.5 </u> feet at a horizontal distance of <u> 5 </u> feet away from the sprinkler head.
  • The spray reaches all the way to the ground at about <u> 10.9 </u> feet away.

The graph shows the x-intercept at about 10.9. That is where the height of the spray is 0 feet above the ground.

7 0
3 years ago
Use a net to find the surface area of the right triangular prism shown below:
Stolb23 [73]
Bottom rectangle = 10*7 = 70
Top rectangle = 8*7 = 56
Side rectangle = 6*7 = 42
Side triangle = (1/2)*8*6 = 24
Side triangle = (1/2)*8*6 = 24
--------------------------------------------------

Total surface area = 70+56+42+24+24 = 216
3 0
4 years ago
Read 2 more answers
Simplify the fraction completly<br> 75/100
jeka57 [31]
The simplest form for 75/100 is 3/4
8 0
3 years ago
Read 2 more answers
There are 27 red or blue marvels in a bag. The number of red marbles is 5 less than 3 time the number of blue marbles. How many
BigorU [14]

Answer:

let R= red

let B= blue

R+B= 27

R=3B-5

3B-5+B=27

3B+B=27+5

4B=32

4B/4= 32/4

B=8

R= 3*8-5

R=24-5

R=19

4 0
4 years ago
A breeder reactor converts uranium-238 into an isotope of plutonium-239 at a rate proportional to the amount of uranium-238 pres
topjm [15]

Let U(t) denote the amount of uranium-238 in the reactor at time t. As conversion to plutonium-239 occurs, the amount of uranium will decrease, so the conversion rate is negative. Because the rate is proportional to the current amount of uranium, we have

\dfrac{\mathrm dU}{\mathrm dt}=-kU

where k>0 is constant. Separating variables and integrating both sides gives

\dfrac{\mathrm dU}U=-k\,\mathrm dt\implies\ln|U|=-kt+C\implies U=Ce^{-kt}

Suppose we start some amount u. This means that at time t=0 we have U(0)=u, so that

u=Ce^{-0k}\implies C=u\implies U=ue^{-kt}

We're given that after 10 years, 99.97% of the original amount of uranium remains. This means (if t is taken to be in years) for some starting amount u,

0.9997u=ue^{-10k}\implies k=-\dfrac{\ln(0.9997)}{10}

The half-life is the time t_{1/2} it takes for the starting amount u to decay to half, 0.5u:

0.5u=ue^{-kt_{1/2}}\implies t_{1/2}=-\dfrac{\ln(0.5)}k=\dfrac{10\ln2}{\ln(0.9997)}

or about 23,101 years. Notice that it doesn't matter what the actual starting amount is, the half-life is independent of that.

7 0
3 years ago
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