Answer is D
(1.5,3)
Explanation:
Substitute
1) 3-2(1.5)=0
So 0=0
2) 3=8(1.5)-9
So 3=3
LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)
<h3>What is the limit of a function ?</h3>
The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.
It is given that
lim x->2 for f(x)
f(x) = 2x+1 x ≤2
f(x)= x² , x >2
When both the function tends to 2
Left Hand Limit
f(x) = 2 *2 +1
f(x) = 5
Right Hand Limit
f(x) = x² ,
f(x) = 4
LHL in not equal to RHL , Therefore the limit does not exists.
To know more about Limit of a Function
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Answer:
Simplifying
4u = 10.24
Solving
4u = 10.24
Solving for variable 'u'.
Move all terms containing u to the left, all other terms to the right.
Divide each side by '4'.
u = 2.56
Simplifying
u = 2.56
Step-by-step explanation:
Domain is the numbers you can use
we can use all real numbers for this one
rangge is the numbers we get from inputting the domain
well, this is a 4th degree, so we need to find the minimum,because the leading coefient is positive so it opens up, and as x approaches negative and positive infinity, then f(x) approaches infnity
find minimum
take derivitive
f'(x)=4x^3-18x^2-8x+54
the zeroes are at about -1.652 and 1.9381 and 4.2145
we use a sign chart
the minimum occurs at hwere the derivitive changes from negative to positive
that is at -1.652 and 4.2145
evaluate f(-1.652) and f(4.2145)
f(-1.652)=-110.626
f(4.2145)=-22.124
the least value is -110.626
that is the minimum
so the domain is all real numbers
range is from -110.626 to infinity
I think the answer is B.(1.33,1)
but i'm not sure..
