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3 years ago

The following shape has 1 pair of parallel sides What is the area of the shape?

Mathematics

1 answer:

Ivanshal [37]3 years ago

6 0

Answer:

67.5

Step-by-step explanation:

Because I know

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There are 24 students in the class. If 12 of them enrolled to the French courses, 13 of them to the Spanish and 7 of them take n

Butoxors [25]

Answer:

1/6 = 0.1667 = 16.67%

Step-by-step explanation:

If there are 24 students in the class and 7 of them take neither courses, we have 17 students that take one or both courses.

To find the students that took both courses, we can use the formula:

N(Spanish or French) = N(Spanish) + N(French) - N(Spanish and French)

17 = 13 + 12 - N(Spanish and French)

N(Spanish and French) = 8

Then, the number of students that are taking only French is:

N(only French) = N(French) - N(Spanish and French)

N(only French) = 12 - 8 = 4

So the probability of chosing a student that took only French is:

P(only French) = N(only French) / N(total)

P(only French) = 4 / 24 = 1/6

6 0

3 years ago

The average temperature in a northern Canadian city is 1 degree Fahrenheit. The actual temperature in January differs by 10 degr

Darya [45]

Answer:

x+10

Step-by-step explanation:

4 0

3 years ago

What Is the value of x in the equation -2/5x=2/5

sdas [7]

The answer is x= -1.

5 0

3 years ago

Read 2 more answers

It was reported that 23% of U.S. adult cellphone owners called a friend for advice about a purchase while in a store. If a sampl

leva [86]

Answer:

$P(X=7)$

And using the probability mass function we got:

$P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271$

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.23)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find the following probability:

$P(X=7)$

And using the probability mass function we got:

$P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271$

5 0

3 years ago

1) A company makes boxes of crackers that should weigh 213g. A

Lesechka [4]

The boxes can weight at most 5 grams less than the desired amount, so they can't be lighter than

$213-5=208$ grams

Similary, they can't weight more than 5 grams more than the desired amount, so they can't be heavier than

$213+5=218$ grams

So, the acceptable range is between 208 and 218.

6 0

4 years ago