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Valentin [98]
2 years ago
11

Please help me asap, tyyyy!!

Mathematics
2 answers:
djyliett [7]2 years ago
7 0

Step-by-step explanation:

Hope this helps and learn well

Tju [1.3M]2 years ago
7 0
There you go this is your answer

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Patulong naman po. pass sa di marunong
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Answer:

Bạn không tử tế :) Đó là một trò đùa

Step-by-step explanation:

Đi qua

4 0
2 years ago
The perimeter of a rectangle equals one and a half times its area. Express the length of the rectangle in terms of the width (us
WITCHER [35]

Answer:

Step-by-step explanation:

let x and y be length and width of rectangle.

Perimeter=2(x+y)

area=xy

2(x+y)=1/2 xy

4(x+y)=xy

4x+4y=xy

x y-4y=4 x

y(x-4)=4 x

y=\frac{4x}{x-4}

4 0
3 years ago
Which of the following sets of angle measures can be used to draw an acute isosceles triangle? Select all that apply. 75°, 30°,
SCORPION-xisa [38]

Answer:

1. 80°, 80°, 40°

2. 60°, 60°, 60°

3. 20°, 140°, 20°

4. 50°, 50°, 80°

5. 75°, 30°, 75°

6. 80°, 55°, 45°

6, 2, and 4

4 0
3 years ago
Read 2 more answers
What is -3/4 multiplied by -1 1/5
MrRa [10]
The answer to this will be a positive multiply 3 and 11 you'll get 33 and multiply 4 and 5 and you'll get 20

33/20
4 0
3 years ago
Read 2 more answers
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
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