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dusya [7]
3 years ago
11

What is the length of the third side of the window frame below? (Figure is not drawn to scale.) A picture of a right triangular

window frame is shown. The longest side has length labeled as 65 inches. The height of the frame is labeled as 60 inches. 10 inches 15 inches 25 inches 30 inches Question 2(Multiple Choice Worth 5 points)
Mathematics
2 answers:
lozanna [386]3 years ago
8 0

Answer:

the awnser is 25

Step-by-step explanation:

bruv down there is right

mojhsa [17]3 years ago
7 0
The answer to your question is 25
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A shop has a sale that offers 20% off all prices.
NeTakaya
I think that the answer is 45% because the sale started off with a 20% discount, but at the end they added another 25% to the sales. So since the sale already started off with 20%, you add 20%+25% which equals 45%. 
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3 years ago
20% of the students in the class play an instrument. if there are 35 students in class, how many play an instrument?
kondor19780726 [428]

Answer:

7 students play an instrument.

Calculation:

35=100%

20%=[20×35]÷100

=7

6 0
3 years ago
A basketball player makes 70% of his free throws the random numbers below represent 20 trials for a simulation let the numbers 0
Nesterboy [21]

Answer:

40%

Step-by-step explanation:

Given the result of the simulation below:

(5,5) (0,6) (9,6) (7,4) (9,1) (7,3) (0,4) (9,3) (2,9) (1,4)

(6,8) (5,3) (1,7) (1,7) (1,8) (3,5) (7,2) (2,1) (0,6) (1,8)

n(S)=20

  • The numbers 0 to 6 represent a made free throw .
  • The numbers 7 to 9 represent a missed free throw.
  • Therefore, any result containing 7 to 9 does not satisfy our requirement that the player makes both throws.

Let Event A be the event that the player made both throws

The pairs in which the player made both throws are:

(5,5) (0,6) (0,4) (1,4) (5,3)  (3,5)  (2,1) (0,6)

n(A)=8

Therefore:

P(A)=\frac{n(A)}{n(S)}=\frac{8}{20}=0.4\\

The probability that the player made both throws is 40%.

6 0
3 years ago
Read 2 more answers
Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
mark bought 168 meters of fencing to enclose an area of pasture for his sheep. he plans to use all of the fencing to make a rect
Anika [276]
The two long sides are 63meters and the shorter sides are 21meters.
7 0
3 years ago
Read 2 more answers
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