This question involves the concepts of projectile motion and launch speed.
(a) The initial launch speed of the projectile is "100 m/s".
(b) The launch angle of the projectile is "53.13°".
<h3>(a) LAUNCH SPEED</h3>
A projectile motion is a motion that takes place on both x and y axes, simultaneously. In this motion the initial launch speed is given by the following formula:
where,
= initial launch speed = ?
= horizontal component of initial launch speed = 60 m/s
= vertical component of initial launch speed = 80 m/s
Therefore,
<h3>(b) LAUNCH ANGLE</h3>
Launch angle is given by th following formula:
Learn more about the projectile motion here:
brainly.com/question/11049671
Answer:
2 m/s²
Explanation:
Given:
v₀ = 0 m/s
v = 20 m/s
t = 10 s
Find: a
a = (v − v₀) / t
a = (20 m/s − 0 m/s) / 10 s
a = 2 m/s²
Answer:
1×10^2
Explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
Answer:
a = 3.27 m/s²
T = 275 N
Explanation:
Given that:
Mass m₁ = 42.p0 kg
Mass m₂ = 21.0 kg
Consider both masses to be in a whole system, then:
The acceleration can be determined as:
Making acceleration the subject in the above formula;
a = 3.27 m/s²
in the string, the tension is calculated using the formula:
T = 274.68 N
T ≅ 275 N
Answer:
2KI + Cl₂ → 2KCl + I₂
Explanation:
The reaction equation is given as:
KI + Cl₂ → KCl + I₂
The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;
aKI + bCl₂ → cKCl + dI₂
Conserving K : a = c
I : a = 2d
Cl : 2b = c
Now let a = 1, c = 1 , d = 
, b = , ;
Multiply through by 2;
a = 2, b = 1 , c = 2, d = 1
2KI + Cl₂ → 2KCl + I₂
