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Elis [28]
4 years ago
8

What is the purpose of a reference point?

Physics
2 answers:
pishuonlain [190]4 years ago
6 0

Answer: <u>To establish a point from which to measure a future distance, or if movement has occurred.</u>

Explanation:

A reference point is a point with respect to which one comes to know whether any movement has occurred or not. A still point is required. When the object changes distance from that point, it means that object has moved. The distance can be calculated from one point to another.

Therefore, A reference point is used to establish a point from which future distance or if movement has occurred is detected.

KengaRu [80]4 years ago
6 0
The purpose of the reference point is to to establish a point from which to measure future distance, or if movement has occurred.
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Compare and contrast sound waves and electromagnetic waves. Any bs answers will be reported. Please hurry!!!
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Answer:

They are both forms of energy.  One has to do with hearing and the other a little bit of light.

Explanation:

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A car is traveling at 8 m/s accelerates at 3.1 m/s^2 to reach a final top speed of 56 m/s. How much time will pass before the ca
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Which are most likely to be used during a routine visit to the dentist?
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Answer:

The most likely items to be used are;

Ultrasound and X-rays

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3 years ago
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The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and
nikitadnepr [17]

Complete question:

The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.

Answer:

The exit velocity is 629.41 m/s

Explanation:

Given;

initial temperature, T₁ = 1200K

initial pressure, P₁ = 150 kPa

final pressure, P₂ = 80 kPa

specific heat at 300 K, Cp = 1004 J/kgK

k = 1.4

Calculate final temperature;

T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}

k = 1.4

T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}}\\\\T_2 = 1200(\frac{80}{150})^{\frac{1.4-1 }{1.4}}\\\\T_2 = 1002.714K

Work done is given as;

W = \frac{1}{2} *m*(v_i^2 - v_e^2)

inlet velocity is negligible;

v_e = \sqrt{\frac{2W}{m} } = \sqrt{2*C_p(T_1-T_2)} \\\\v_e = \sqrt{2*1004(1200-1002.714)}\\\\v_e = \sqrt{396150.288} \\\\v_e = 629.41  \ m/s

Therefore, the exit velocity is 629.41 m/s

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3 years ago
What is the difference between temperature and heat<br>​
uysha [10]

Explanation:

Heat is a form of energy that can transfer from hot body to cold body.Temperature is the degree of hotness and coldness of a body.

Heat is measured in joules, but temp. is measured in Kelvin

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