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steposvetlana [31]
3 years ago
12

A ball, initially at rest, reaches a speed of 20 m/s at the bottom of the apparatus. If it takes the ball 10 seconds to reach th

e bottom, what is the ball’s average acceleration?
Physics
1 answer:
MariettaO [177]3 years ago
3 0

Answer:

2 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 20 m/s

t = 10 s

Find: a

a = (v − v₀) / t

a = (20 m/s − 0 m/s) / 10 s

a = 2 m/s²

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A spring has a constant k= 10.32 N/m and is hung vertically. A 0.400kg mass is suspended from the spring. What is the displaceme
alukav5142 [94]

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displacement (x) = 0.003798 meters

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Fg = m*g

then:

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Ftot = 0

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4 0
3 years ago
Below is a physics question
Allisa [31]

Explanation:

 i1=1ampere

i1+i2=I

VA−VB=i1×3Ω=i2×6

⇒1×3=i2×6

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equivalent circuit

Refer image .2

From KVL

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8 0
3 years ago
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