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2 years ago

Over a 14-day period, Jamal went to the store 4 times. Based on this

Mathematics

1 answer:

user100 [1]2 years ago

3 0

Answer:

He will go to the store 10 times in a 5-week period.

Step-by-step explanation:

We can assume that in one week, Jamal went to the store 2 times, considering he went to the store 4 times in 2 weeks. Next, we can assume that he will go to the store 10 times in 5 weeks, since 2×5=10.

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Mr. Wilson is giving his students a vocabulary test tomorrow over all the terms they have learned from this semester. Today, he

Y_Kistochka [10]

The population in the above situation is the total number of students under Mr. Wilson.

A sample is a part of the population that may best represent the population. There is no sample in the above situation because Mr. Wilson made all students pick 5 note cards. He will be able to determine the performance of each student based on their performance in picking 5 note cards and defining the terms in each card.

5 0

2 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

4 0

2 years ago

tammy is 14 years old. she has a younger sister and an older brother. her sister is 12. the mean of all their ages is 14. how ol

mafiozo [28]

Answer:

Step-by-step explanation:

To solve, we can use an equation finding the average of the siblings'ages.

$\frac{14 + 12 + x}{3} = 14 \\ \ 14 + 12 + x = 42 \\ x = 42 - 14 - 12 \\ x = 16$

7 0

3 years ago

(NO FAKE LINKS PLS) Use the geometric mean to find the value of e

dem82 [27]

Answer:

I have already answered this in your last question:)

4 0

3 years ago

What's 25.65 divided by 15

Rasek [7]

25.65 ÷ 15 = 1.71

So, the answer to this problem is 1.17

3 0

3 years ago

Read 2 more answers