The answer is c. communitive
18c-30d+36 < that’s the answer
Answer: 45.03%
To find the answer for this problem, you first need to find the z-score for a value of 19.25.
The z-score is the number of standard deviations from the mean.
Here is the work for our z-score:
19.25 - 20 = -0.75 / 6 = -0.125
Now, you just have to use a standard normal distribution table and look up the probability for a z-score of -0.125. I used the average of the probability for z-scores of -0.12 and -0.13 to get 45.03%.
Answer:
1/9 chance
Step-by-step explanation:
Answer:
a) r₁₂ = 104.36
In general, rₙ = arⁿ⁻¹
b)
- rabbit food consumed during the 10th year is approximately 832 pounds
- rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds
Step-by-step explanation:
Given that:
r1 = 30 and a farm grows by 12%
a = 30 and the common ratio r = 1.12
now
n r
1 30.00
2 33.60
3 37.63
4 42.15
5 47.21
6 52.87
7 59.21
8 66.32
9 74.28
10 83.19
11 93.18
12 104.36
Therefore r₁₂ = 104.36
In general, rₙ = arⁿ⁻¹
b)
if each rabbit consume 10 lbs of rabbit food each year
n r food consumed(lbs)
1 30.00 300
2 33.60 336
3 37.63 376
4 42.15 422
5 47.21 472
6 52.87 529
7 59.21 592
8 66.32 663
9 74.28 743
10 83.19 832
total 5265
Therefore, the rabbit food consumed during the 10th year is approximately 832 pounds
And the rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds