All categories

1 year ago

I can’t seem to get the answer right. What is log 10000?

Mathematics

2 answers:

olga nikolaevna [1]1 year ago

8 0

Answer:

the answer is for

Step-by-step explanation:

have a great day

djverab [1.8K]1 year ago

7 0

Answer:

$log(10000) = 4$

Step-by-step explanation:

Count the number of zeros, if it's a perfect power of 10. :)

You might be interested in

The length of an object is measured as 34.8 centimeters. What is this measurement in scientific notation?

harkovskaia [24]

Answer:

34.8 x 10 to the power of 0.

Step-by-step explanation:

hope this helps

3 0

2 years ago

State of the given functions are inverses. Part 3. NO LINKS!!!!

Effectus [21]

Answer:

h(x)=-x-1

let y =-x-1

interchanging role of x & y

x=-y-1

y=-x-1

h-¹(x)=-x-1

again

f(x)=(2-3x)/2

let

y=(2-3x)/2

interchanging role of x & y

x=(2-3y)/2

2x-2=-3y

y=(2-2x)/3

f-¹(x)=(2-2x)/3

Given function are not inverse of each other.

10.

f(x)=-x+3

let y=-x+3

interchanging role of x & y

x=-y+3

y=3-x

f-¹(x)=-x+3

equal to g(x)=-x+3

Given function are inverse of each other.

8 0

2 years ago

Read 2 more answers

Which pair is a pair of vertical angles?

Mariulka [41]

Answer:

Angles that are directly across from each other

Step-by-step explanation:

Vertical angles are angles that are directly across from each other, forming an x. They always have the same degree

8 0

2 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

1 year ago

Can a vector have a component greater than the vector's magnitude ?

Mars2501 [29]

Answer: No, it can never be greater. At most it can be equal though.

5 0

2 years ago