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3 years ago

1/4 of what number is 3/8

2 answers:

5 0

You can multiply 3/8 by 1/4, getting 1.5
You can check by taking 1/4 of 1.5. 1.5 times 1/4 = 3/8

So the answer would be 1.5

ArbitrLikvidat [17]3 years ago

4 0

1.5 is the answer......

You might be interested in

A line passes through the point (0,2) and has a slope of -1/2 what is the equation of the line

emmasim [6.3K]

Answer:

y = -1/2x + 2

Step-by-step explanation:

A line in slope-intercept form in y = mx + b

"m" is the slope

"b" is the y-intercept

x and y represent points on the graph

To write an equation, you need "m" and "b".

We already know m = -1/2

The point (0, 2) is the y-intercept. The y-intercept occurs when x = 0.

Points are in the form (x , y), so x = 0 and y = 2.

Therefore b = 2.

Substitute m = -1/2 and b = 2 into the equation:

y = mx + b

y = -1/2x + 2

5 0

3 years ago

Find the length of side y

Serggg [28]

Answer:

$\large\boxed{y=76.3359\ cm\approx76.3\ cm}$

Step-by-step explanation:

Use cosine:

$cosine=\dfrac{adjacent}{hypotenuse}$

We have

$adjacent=73\ cm\\hypotenuse=y$

and the angle 17°.

$\cos17^o\approx0.9563$

Substitute:

$\dfrac{73}{y}=0.9563$ convert the decimal to the fraction

$\dfrac{73}{y}=\dfrac{9563}{10000}$ cross multiply

$9563y=730000$ divide both sides by 9563

$y=\dfrac{730000}{9563}$

$y\approx76.3359$

8 0

3 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

2 years ago

Read 2 more answers

£8001 is shared equally between 9 people. How much does each person get?

Alika [10]

£888.9 because you can divide £8001 buy 9

5 0

2 years ago

Determine if the described set is a subspace. Assume a, b, and c are real numbers. The subset of R3 consisting of vectors of the

AveGali [126]

Answer:

Not a subspace

Step-by-step explanation:

(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.

7 0

2 years ago