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BabaBlast [244]
2 years ago
11

Triangle MNP has vertices M(5,4), N(5,9), and P(−1,4). What are the coordinates of the image of point P after the triangle is ro

tated 180° clockwise about the origin?Immersive Reader
P'(1, 4)
P'(-1, -4)
P'(1,- 4)
P'(4, 1)
P'(-4, -1)
P'(4, -1)
Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
5 0

Answer:

P' (1, -4)

Step-by-step explanation:

Hey girl, your pfp be making me want you a lott.

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gayaneshka [121]
Are we solving for h?
V=πr²h+r²h
V=h(πr²+r²)
V/(πr²+r²) = h
8 0
3 years ago
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1212154545454 121 4654546+56546546464454-5454881/3148486*5
lesya692 [45]
Usually when you add big numbers together, you get a result of exponents involved :) answer for your question : 1.212154551 e^22
5 0
3 years ago
Ophelia read ⅕ of her 60 pages book in ½ hour. How many pages can she read in one hour?
marishachu [46]

Answer:

She can read 24 pages in one hour.

Step-by-step explanation:

\frac{1}{5}*2 = \frac{2}{5}*60pages = 24pages

<em>hope this helps, good luck :)</em>

8 0
3 years ago
Read 2 more answers
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
3 years ago
Anita can clean a typical pool in 8 hours. Chao can clean a typical pool in 6 hours. How long should it take Anita and Chao work
ivanzaharov [21]
Anita can clean 1/8 portion of the pool in 1 hour

Chao can clean 1/6 portion of the pool in 1 hour

Both of them working together can clean 1/8 + 1/6 = 7/24 portion of the pool in 1 hour

Therefore, it will take both of the working together 1/(7/24) = 24/7 or 3 3/7 hours to clean a typical pool.
3 0
3 years ago
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